603. Consecutive Available Seats

select distinct c1.id from cinema c1, cinema c2

where abs(c1.id-c2.id) =1 and c1.free = 1 and c2.free =1

group by c1.id

转载于:https://www.cnblogs.com/ffeng0312/p/9829006.html

603. Consecutive Available Seats相关推荐

LeetCode All in One 题目讲解汇总(持续更新中...)
原文地址:https://www.cnblogs.com/grandyang/p/4606334.html 终于将LeetCode的大部分题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开 ...
【sql】leetcode习题 (共 42 题)
[175]Combine Two Tables (2018年11月23日,开始集中review基础) Table: Person +-------------+---------+ | Column ...
谈谈我对前端组件化中“组件”的理解，顺带写个Vue与React的demo
谈谈我对前端组件化中"组件"的理解,顺带写个Vue与React的demo 前言前端已经过了单兵作战的时代了,现在一个稍微复杂一点的项目都需要几个人协同开发,一个战略级别的APP的 ...
leetcode 数据库题目全部题解
来源链接:https://leetcode-cn.com/circle/article/vGr1Mc/ 对数据库专题下每道题目,包括会员题目,都做了详细的题解. 题解内容通常有这么几个部分,题目简述. ...
1096 Consecutive Factors
1. 对于题目描述中 list the smallest sequence of the consecutive factors 正确理解是:如果有多组连续因子,输出开头因子最小的那个序列(一开始理解 ...
LeetCode 829. Consecutive Numbers Sum--笔试题--C++解法
LeetCode 829. Consecutive Numbers Sum–笔试题–C++解法 LeetCode题解专栏:LeetCode题解 LeetCode 所有题目总结:LeetCode 所有题 ...
HDOJ(HDU) 1977 Consecutive sum II(推导、、)
Problem Description Consecutive sum come again. Are you ready? Go ~~ 1 = 0 + 1 2+3+4 = 1 + 8 5+6+7+8 ...
PAT甲级1096 Consecutive Factors ：[C++题解]连续的因子、约数
文章目录题目分析题目链接题目分析来源:acwing 题意重述:1个正整数N的因子中可能存在若干连续的数字.比如 N =630 ,N = 3 * 5 * 6 *7,这里连续的因子是5 *6 * ...
聊聊flink的consecutive windowed operations
为什么80%的码农都做不了架构师?>>> 序本文主要研究一下flink的consecutive windowed operations 实例 DataStream<In ...

603. Consecutive Available Seats

603. Consecutive Available Seats相关推荐

最新文章

热门文章