importjava.util.ArrayList;importjava.util.Collections;importjava.util.HashMap;importjava.util.List;importjava.util.Set;public classTest {public static voidmain(String[] args) {/*思路分析:

1,生成牌:用map集合保存54张牌,且从1-54数字对应起来*/List color = new ArrayList<>();

List point = new ArrayList<>();

Collections.addAll(color,"♥","♠","♣","♦");

Collections.addAll(point,"A","2","3","4","5","6","7","8","9","10","J","Q","K");

HashMap poker = new HashMap<>();

poker.put(0, "大王");

poker.put(1, "小王");int serialNum = 2;for(String d : point) {for(String c : color) {

poker.put(serialNum,c+d);

serialNum++;

}

}//一副扑克牌生成完成//System.out.println(poker);//输出验证//2,利用序号->洗牌->发牌//

//获取双列map集合中的所有key值

Set key =poker.keySet();//利用有参构造方法来初始化单列List集合

List pokerNum = newArrayList(key);//System.out.println(pokerNum);//获取所有key值完毕

Collections.shuffle(pokerNum);//利用三个玩家容器和一个底牌容器存储(容器使用单列集合,便于排序,利用序号(也就是双列集合中key值)取对应的牌面就行了)

List player1 = new ArrayList<>();

List player2 = new ArrayList<>();

List player3 = new ArrayList<>();

List lastPoker = new ArrayList<>();for (int i = 0; i < pokerNum.size(); i++) {if(i >= 51) {//注意要添加的值是扑克打乱后的值,非遍历的序号值

lastPoker.add(pokerNum.get(i));

}else if(i % 3 == 1){

player1.add(pokerNum.get(i));

}else if(i % 3 == 2) {

player2.add(pokerNum.get(i));

}else{

player3.add(pokerNum.get(i));

}

}//发牌完毕,整理牌面

Collections.sort(lastPoker);

Collections.sort(player1);

Collections.sort(player2);

Collections.sort(player3);//3.利用玩家获得牌面的序号,取牌//每个玩家遍历一次

System.out.print("底牌:");for(Integer i : lastPoker) {

String str=poker.get(i);

System.out.print(str+" ");

}

System.out.println();

System.out.print("玩家1:");for(Integer i : player1) {

String str=poker.get(i);

System.out.print(str+" ");

}

System.out.println();

System.out.print("玩家2:");for(Integer i : player2) {

String str=poker.get(i);

System.out.print(str+" ");

}

System.out.println();

System.out.print("玩家3:");for(Integer i : player3) {

String str=poker.get(i);

System.out.print(str+" ");

}

}

}