Oracle数据库字符串分割的处理实现。

1.首先要先创建数组

create or replace type t_ret_table is table of varchar2(20);

2.利用自定义函数实现一，利用函数返回数组．

create or replace function f_split_string(var_str in string,var_split In String) return t_ret_table

is

var_out t_ret_table;

var_tmp varchar2(4000);

var_element varchar2(4000);

begin

var_tmp := var_str;

var_out := t_ret_table();

–如果存在匹配的分割符

while instr(var_tmp,var_split)>0 loop

var_element := substr(var_tmp,1,instr(var_tmp,var_split)-1);

var_tmp := substr(var_tmp,instr(var_tmp,var_split)+length(var_split),length(var_tmp));

var_out.extend(1);

var_out(var_out.count) := var_element;

end loop;

var_out.extend(1);

var_out(var_out.count) := var_tmp;

return var_out;

end f_split_string;

3.利用 pipelined Function 函数实现.

create or replace function f_split(var_str in string,var_split In String) return t_ret_table PIPELINED

as

var_tmp varchar2(4000);

var_element varchar2(4000);

n_length Number := length(var_split);

begin

var_tmp := var_str;

while instr(var_tmp,var_split)>0 loop

var_element := substr(var_tmp,1,instr(var_tmp,var_split)-1);

var_tmp := substr(var_tmp,instr(var_tmp,var_split)+n_length,length(var_tmp));

pipe row(var_element);

end loop;

pipe row(var_tmp);

return;

end f_split;

4.字符串分割的函数，返回数组，但是也可以使用语句查询

select * from table(f_split_string(‘hanjs-zhaos’,'-’));

5.对于需要排序的，完全可以在查询时体现．

注意：查询出来的列名为 Column_Value

6.怎样支掉字符串中逗号间重复的字符

如 ‘,1,2,5,9,1,2,5,9,1,2,9,1,2,9,1,2,3,9,1,2,3,9,1,2,9,1,2,9,1,2,3,9,1,2,3,9,’怎样支掉字符串中逗号间重复的字符,并将字符升序排列，得到

‘,1,2,3,5,9,’

百思不得其解，是高手的试一下。

解答：

select col from(

select sys_connect_by_path(col,’,')||’,’ col,level from(

select col,row_number() over(order by rownum) rn from (

select distinct substr(col,instr(col,’,',1,rownum)+1,instr(col,’,',1,rownum+1)-instr(col,’,',1,rownum)-1) col from (

select ‘,1,2,5,9,1,2,5,9,1,3,9,’ col from dual

) connect by rownum

)

)

connect by prior rn = rn -1 order by level desc

) where rownum=1