本文实例讲述了python获取一组汉字拼音首字母的方法。分享给大家供大家参考。具体实现方法如下：

#!/usr/bin/env python

# -*- coding: utf-8 -*-

def multi_get_letter(str_input):

if isinstance(str_input, unicode):

unicode_str = str_input

else:

try:

unicode_str = str_input.decode('utf8')

except:

try:

unicode_str = str_input.decode('gbk')

except:

print 'unknown coding'

return

return_list = []

for one_unicode in unicode_str:

return_list.append(single_get_first(one_unicode))

return return_list

def single_get_first(unicode1):

str1 = unicode1.encode('gbk')

try:

ord(str1)

return str1

except:

asc = ord(str1[0]) * 256 + ord(str1[1]) - 65536

if asc >= -20319 and asc <= -20284:

return 'a'

if asc >= -20283 and asc <= -19776:

return 'b'

if asc >= -19775 and asc <= -19219:

return 'c'

if asc >= -19218 and asc <= -18711:

return 'd'

if asc >= -18710 and asc <= -18527:

return 'e'

if asc >= -18526 and asc <= -18240:

return 'f'

if asc >= -18239 and asc <= -17923:

return 'g'

if asc >= -17922 and asc <= -17418:

return 'h'

if asc >= -17417 and asc <= -16475:

return 'j'

if asc >= -16474 and asc <= -16213:

return 'k'

if asc >= -16212 and asc <= -15641:

return 'l'

if asc >= -15640 and asc <= -15166:

return 'm'

if asc >= -15165 and asc <= -14923:

return 'n'

if asc >= -14922 and asc <= -14915:

return 'o'

if asc >= -14914 and asc <= -14631:

return 'p'

if asc >= -14630 and asc <= -14150:

return 'q'

if asc >= -14149 and asc <= -14091:

return 'r'

if asc >= -14090 and asc <= -13119:

return 's'

if asc >= -13118 and asc <= -12839:

return 't'

if asc >= -12838 and asc <= -12557:

return 'w'

if asc >= -12556 and asc <= -11848:

return 'x'

if asc >= -11847 and asc <= -11056:

return 'y'

if asc >= -11055 and asc <= -10247:

return 'z'

return ''

def main(str_input):

a = multi_get_letter(str_input)

b = ''

for i in a:

b= b+i

print b

if __name__ == "__main__":

str_input=u'欢迎你'

main(str_input)

希望本文所述对大家的Python程序设计有所帮助。

时间： 2015-06-28