LeetCode 212. Word Search II

Solution1:我的答案
暴力搜索。。基于第79题的答案，真的是非常之慢啊！！！
快的方法均是基于字典树的方法，真是复杂。。

class Solution {
public:vector<string> findWords(vector<vector<char>>& board, vector<string>& words) {set<string> res;if (!board.size() || !board[0].size() || !words.size())return {};int m = board.size(), n = board[0].size();for (auto word: words) {bool symbol = false;for (int i = 0; i < m; i++) {for (int j = 0; j < n; j++) {vector<vector<int> > visited(m, vector<int>(n, 0));//0:未用;1:用过string temp;int len = 0;symbol = my_search(board, i, j, len, word, visited);if (symbol) res.insert(word);}}}return vector<string> (res.begin(), res.end());}bool my_search(vector<vector<char>>& board, int i, int j, int len,string& word, vector<vector<int> >& visited) {if (len == word.size()) return true;if (i >= 0 && i < board.size() && j >= 0 && j < board[0].size() && visited[i][j] == 0 && board[i][j] == word[len]) {len++;visited[i][j] = 1;if (my_search(board, i - 1, j, len, word, visited) || my_search(board, i + 1, j, len, word, visited)|| my_search(board, i, j - 1, len, word, visited)|| my_search(board, i, j + 1, len, word, visited))return true;len--;visited[i][j] = 0;}return false;}
};

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【DFS + Backtracking】LeetCode 212. Word Search II

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