codewars练习（javascript）-2021/2/5

文章目录

codewars-js练习
- 2021/2/5
- - github 地址
  - 【1】<5kyu>【Regex Password Validation】
  - 【2】<6kyu>【Two Sum】
  - 【3】<5kyu>【String incrementer】

codewars-js练习

2021/2/5

github 地址

my github地址，上面有做的习题记录，不断更新…

【1】<5kyu>【Regex Password Validation】

You need to write regex that will validate a password to make sure it meets the following criteria:

At least six characters long
contains a lowercase letter
contains an uppercase letter
contains a number

Valid passwords will only be alphanumeric characters.

您需要编写正则表达式来验证密码，以确保它符合以下条件:

至少6个字符/包含小写字母/包含大写字母/包含许多/有效的密码只能是字母数字字符。

example：

('djI38D55'), 'djI38D55 - Expected true'
('a2.d412'), 'a2.d412 - Expected false'

solution

<script type="text/javascript">function validate(password) {return /^(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])\w{6,}$/g.test(password);}// 验证console.log(validate('djI38D55')); // trueconsole.log(validate('a2.d412')); //falseconsole.log(validate('123'));//falseconsole.log(validate('jfkdfj3j'));//falseconsole.log(validate('JHD5FJ53'));//false</script>

【2】<6kyu>【Two Sum】

Write a function that takes an array of numbers (integers for the tests) and a target number. It should find two different items in the array that, when added together, give the target value. The indices of these items should then be returned in a tuple like so: (index1, index2).

返回相加等于目标和的两个index

example：

twoSum [1, 2, 3] 4 //(0, 2)
twoSum [1234,5678,9012] 14690//[1,2]

solution

<script type="text/javascript">function twoSum(numbers, target) {// console.log(numbers,target);for(var i=0;i<numbers.length;i++){for(var j=i+1;j<numbers.length;j++){if(numbers[i] + numbers[j] == target){// console.log(numbers[i]+numbers[j] == target);return [i,j];}}          }}// 验证console.log(twoSum([1,2,3],4)); // [0,2]console.log(twoSum([1234,5678,9012],14690));//[1,2])</script>

【3】<5kyu>【String incrementer】

Your job is to write a function which increments a string, to create a new string.

If the string already ends with a number, the number should be incremented by 1.
If the string does not end with a number. the number 1 should be appended to the new string.

你的工作是写一个函数来增加一个字符串，来创建一个新的字符串。

如果字符串已经以一个数字结束，则该数字应该加1;如果字符串没有以数字结束。数字1应该被附加到新的字符串中。

example：

foo -> foo1foobar23 -> foobar24foo0042 -> foo0043foo9 -> foo10foo099 -> foo100

solution

<script type="text/javascript">function incrementString (strng) {console.log(strng);var arr = strng.split('');var num = strng.match(/(\d*)$/)[0];// console.log(typeof num);var len = strng.length - num.length;if(num !=0){for(var i=num.length-1;i>0;i--){if(parseInt(num[i])==0){// console.log(strng.substring(0,len+i+1));// console.log(strng.substring(strng.length-1,strng.length))if(strng.substring(strng.length-1,strng.length) == 9){return strng.substring(0,len+i) + (parseInt(num)+1);}return strng.substring(0,len+i+1) + (parseInt(num)+1);// if()}}return strng.substring(0,len) + (parseInt(num)+1);}else{console.log((/0{1,}/g).test(num))// console.log('2')if((/0{1,}/g).test(num)){for(var i=num.length-1;i>0;i--){if(parseInt(num[i])==0){return strng.substring(0,len+i) + (parseInt(num)+1);}}}else{return strng + '1';}}}// 验证console.log(incrementString('foo')); // foo1// console.log(incrementString('foo9'));// foo10// console.log(incrementString('foobar001'));// foobar002console.log(incrementString('foobar000'))//foobar001</script>

以上为自己思路供大家参考，可能有更优的思路。最后一道祈求最优解，感觉我写的很繁琐