前言

最近因为工作原因，发现一个Python的时间组件，很好用分享出来！(忘记作者名字了，在这里先感谢了)，下面话不多说，来一起看看详细的介绍吧。

示例代码：

# -*- coding: utf-8 -*-

'''获取当前日期前后N天或N月的日期'''

from time import strftime, localtime

from datetime import timedelta, date

import calendar

year = strftime("%Y", localtime())

mon = strftime("%m", localtime())

day = strftime("%d", localtime())

hour = strftime("%H", localtime())

min = strftime("%M", localtime())

sec = strftime("%S", localtime())

def today():

'''''

get today,date format="YYYY-MM-DD"

'''''

return date.today()

def todaystr():

'''

get date string, date format="YYYYMMDD"

'''

return year + mon + day

def datetime():

'''''

get datetime,format="YYYY-MM-DD HH:MM:SS"

'''

return strftime("%Y-%m-%d %H:%M:%S", localtime())

def datetimestr():

'''''

get datetime string

date format="YYYYMMDDHHMMSS"

'''

return year + mon + day + hour + min + sec

def get_day_of_day(n=0):

'''''

if n>=0,date is larger than today

if n<0,date is less than today

date format = "YYYY-MM-DD"

'''

if (n < 0):

n = abs(n)

return date.today() - timedelta(days=n)

else:

return date.today() + timedelta(days=n)

def get_days_of_month(year, mon):

'''''

get days of month

'''

return calendar.monthrange(year, mon)[1]

def get_firstday_of_month(year, mon):

'''''

get the first day of month

date format = "YYYY-MM-DD"

'''

days = "01"

if (int(mon) < 10):

mon = "0" + str(int(mon))

arr = (year, mon, days)

return "-".join("%s" % i for i in arr)

def get_lastday_of_month(year, mon):

'''''

get the last day of month

date format = "YYYY-MM-DD"

'''

days = calendar.monthrange(year, mon)[1]

mon = addzero(mon)

arr = (year, mon, days)

return "-".join("%s" % i for i in arr)

def get_firstday_month(n=0):

'''''

get the first day of month from today

n is how many months

'''

(y, m, d) = getyearandmonth(n)

d = "01"

arr = (y, m, d)

return "-".join("%s" % i for i in arr)

def get_lastday_month(n=0):

'''''

get the last day of month from today

n is how many months

'''

return "-".join("%s" % i for i in getyearandmonth(n))

def getyearandmonth(n=0):

'''''

get the year,month,days from today

befor or after n months

'''

thisyear = int(year)

thismon = int(mon)

totalmon = thismon + n

if (n >= 0):

if (totalmon <= 12):

days = str(get_days_of_month(thisyear, totalmon))

totalmon = addzero(totalmon)

return (year, totalmon, days)

else:

i = totalmon / 12

j = totalmon % 12

if (j == 0):

i -= 1

j = 12

thisyear += i

days = str(get_days_of_month(thisyear, j))

j = addzero(j)

return (str(thisyear), str(j), days)

else:

if ((totalmon > 0) and (totalmon < 12)):

days = str(get_days_of_month(thisyear, totalmon))

totalmon = addzero(totalmon)

return (year, totalmon, days)

else:

i = totalmon / 12

j = totalmon % 12

if (j == 0):

i -= 1

j = 12

thisyear += i

days = str(get_days_of_month(thisyear, j))

j = addzero(j)

return (str(thisyear), str(j), days)

def addzero(n):

'''''

add 0 before 0-9

return 01-09

'''

nabs = abs(int(n))

if (nabs < 10):

return "0" + str(nabs)

else:

return nabs

def get_today_month(n=0):

'''''

获取当前日期前后N月的日期

if n>0, 获取当前日期前N月的日期

if n<0, 获取当前日期后N月的日期

date format = "YYYY-MM-DD"

'''

(y, m, d) = getyearandmonth(n)

arr = (y, m, d)

if (int(day) < int(d)):

arr = (y, m, day)

return "-".join("%s" % i for i in arr)

if __name__ == "__main__":

print today()

print todaystr()

print datetime()

print datetimestr()

print get_day_of_day(20)

print get_day_of_day(-3)

print get_today_month(-3)

print get_today_month(3)

print get_today_month(19)

总结

以上就是这篇文章的全部内容了，希望本文的内容对大家的学习或者工作能带来一定的帮助，如果有疑问大家可以留言交流，谢谢大家对脚本之家的支持