1124 Raffle for Weibo Followers

题目大意：

m条微博转发记录，第一个获奖者编号为s，每间隔n个就是下一个获奖者。但是没人只能拿一次奖，如果当前位置的人已经拿过了就向下顺延。

解题思路：

小模拟。
代码如下：

#include<iostream>
#include<cstdio>
#include<cstring>
#include<map>
using namespace std;
map<string,int> win;
string forwar[1100];
int main()
{int n,m,s,cont=0;cin>>n>>m>>s;for(int i=1;i<=n;i++)cin>>forwar[i];bool flag=false;while(s<=n){if(win[forwar[s]]==0)//没有获奖 {cout<<forwar[s]<<endl;win[forwar[s]]=1;//标记这个人已经获奖 flag=true;s+=m;//跳过m个人 }else s++;}if(!flag)cout<<"Keep going..."<<endl;return 0;
}

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1124 Raffle for Weibo Followers

题目大意：

解题思路：

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