首先，要想得到想要的空格，将\s*替换为\s*?，使其非贪心。在

第一个修复：>>> re.compile(r'(((iphone|games|mac)\s*?)+)', re.I).sub(r'\1', sentence)

'I love downloading iPhone games from my mac.'

不幸的是，一旦\s*是非贪心的，它就会拆分短语，如您所见。没有它，它是这样的，将两者组合在一起：

^{pr2}$

我还不知道怎么解决这个问题。在

还要注意的是，我在+的旁边加了一组括号，这样所有的匹配都会被捕捉到-这就是区别。在

进一步更新：事实上，我可以想出一个办法来避开它。你决定你是否想要那样。在>>> regex = re.compile(r'((iphone|games|mac)(\s*(iphone|games|mac))*)', re.I)

>>> regex.sub(r'\1', sentence)

'I love downloading iPhone games from my mac.'

更新：考虑到您关于单词边界的观点，我们只需要添加单词边界匹配器\b的几个实例。在>>> regex = re.compile(r'(\b(iphone|games|mac)\b(\s*(iphone|games|mac)\b)*)', re.I)

>>> regex.sub(r'\1', 'I love downloading iPhone games from my mac')

'I love downloading iPhone games from my mac'

>>> regex.sub(r'\1', 'I love downloading iPhone gameses from my mac')

'I love downloading iPhone gameses from my mac'

>>> regex.sub(r'\1', 'I love downloading iPhoney games from my mac')

'I love downloading iPhoney games from my mac'

>>> regex.sub(r'\1', 'I love downloading iPhoney gameses from my mac')

'I love downloading iPhoney gameses from my mac'

>>> regex.sub(r'\1', 'I love downloading miPhone gameses from my mac')

'I love downloading miPhone gameses from my mac'

>>> regex.sub(r'\1', 'I love downloading miPhone games from my mac')

'I love downloading miPhone games from my mac'

>>> regex.sub(r'\1', 'I love downloading iPhone igames from my mac')

'I love downloading iPhone igames from my mac'