1 ///<summary>  2 ///   统计一段时间内有多少个星期几  3 ///</summary>  4 ///<param   name= "AStart "> 开始日期 </param>  5 ///<param   name= "AEnd "> 结束日期 </param>  6 ///<param   name= "AWeek "> 星期几 </param>  7 ///<returns> 返回个数 </returns>  8 public   int   TotalWeeks(DateTime   AStart,   DateTime   AEnd,   DayOfWeek   AWeek)  9 { 10         TimeSpan   vTimeSpan   =   new   TimeSpan(AEnd.Ticks   -   AStart.Ticks); 11         int   Result   =   (int)vTimeSpan.TotalDays   /   7; 12         for   (int   i   =   0;   i   <=   vTimeSpan.TotalDays   %   7;   i++) 13                 if   (AStart.AddDays(i).DayOfWeek   ==   AWeek) 14                         return   Result   +   1; 15         return   Result; 16 }   /*   TotalWeeks   */ 17 18 private   void   button1_Click(object   sender,   EventArgs   e) 19 { 20         Console.WriteLine(TotalWeeks(new   DateTime(2007,   06,   01),   21                 new   DateTime(2007,   06,   30),   DayOfWeek.Monday)); 22 } 

int year = DateTime.Now.Year;int month = DateTime.Now.Month;

DateTime firstDayOfThisMonth = new DateTime(year, month, 1);DateTime lastDayOfThisMonth = new DateTime(year, month, DateTime.DaysInMonth(year, month));

select DATEPART(WEEK,DATEADD(MONTH, 1, GETDATE() - DAY(GETDATE()) + 1) - 1)//当前月最后一天是第几周select DATEPART(WEEK,GETDATE() - DAY(GETDATE()) + 1 )//当前月第一天是第几周select DATEPART(WEEK,DAY(DATEADD(MONTH, 1, GETDATE() - DAY(GETDATE()) + 1) - 1 -(GETDATE() - DAY(GETDATE()) + 1)))//当前月总共有几周

 int year = DateTime.Now.Year;int month = DateTime.Now.Month;            DateTime firstDay = new DateTime(year, month, 1);            DateTime lastDay= new DateTime(year, month, DateTime.DaysInMonth(year, month));

//一.找到第一周的最后一天（先获取1月1日是星期几，从而得知第一周周末是几）            int firstWeekend=firstDay.DayOfYear+(7-Convert.ToInt32(firstDay.DayOfWeek));

//二.获取今天是一年当中的第几天            int currentDay =lastDay.DayOfYear;//三.（最后一天 减去 第一周周末那一天）/7 等于 距第一周有多少周 再加上第一周的1 就是这个月的周数//刚好考虑了惟一的特殊情况就是，今天刚好在第一周内，那么距第一周就是0 再加上第一周的1 最后还是1          Response.Write(Convert.ToInt32(Math.Ceiling((currentDay - firstWeekend) / 7.0)) + 1);