[Leetcode]100. Same Tree -David

Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

思路：同时递归两棵树，如果节点值不相等或者一棵树已经递归到头了而另一棵还没有，返回false;

 1 /**
 2  * Definition for a binary tree node.
 3  * public class TreeNode {
 4  *     int val;
 5  *     TreeNode left;
 6  *     TreeNode right;
 7  *     TreeNode(int x) { val = x; }
 8  * }
 9  */
10 class Solution {
11     public boolean isSameTree(TreeNode p, TreeNode q) {
12         if (p==null&&q==null)
13             return true;                 //一开始如果传进两颗空树，返回true
14         if ((p==null&&q!=null)||(p!=null&&q==null))
15             return false;                //递归过程中，一棵树递归到头了，而另一颗没有
16         if (p.val!=q.val)
17             return false;
18         return isSameTree(p.left,q.left)&&isSameTree(p.right,q.right);
19                                               // 同时递归
20     }
21 }

转载于:https://www.cnblogs.com/David-Lin/p/7692589.html

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