LeetCode 124. Binary Tree Maximum Path Sum

参考链接：http://zxi.mytechroad.com/blog/tree/leetcode-124-binary-tree-maximum-path-sum/
Solution1：

Time complexity O(n)O(n)O(n)
Space complexity O(h)O(h)O(h)
代码如下：
花花酱讲的就是好啊！

/*** Definition for a binary tree node.* struct TreeNode {*     int val;*     TreeNode *left;*     TreeNode *right;*     TreeNode(int x) : val(x), left(NULL), right(NULL) {}* };*/
class Solution {
public:int maxPathSum(TreeNode* root) {if (!root) return 0;int ans = INT_MIN;my_PathSum(root, ans);//ans保存了在递归过程中的最大值，return ans; //而此函数的返回值是经过根结点的最大路径和,经过根结点的未必是整体最大的故该返回值无用}int my_PathSum(TreeNode* root, int &ans) {if (!root) return 0;int l = max(0, my_PathSum(root->left, ans));int r = max(0, my_PathSum(root->right, ans));int sum = l + r + root->val;ans = max(ans, sum);//ans保存着经过当前root结点时的最大路径和return root->val + max(l, r);//返回单边值}
};

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