由于您尚未发布要调用的网址，因此我只能提供一些提示。

即使HtmlUnit在幕后发挥了很多魔力，您也需要对所有Web技术有基本的了解

从代码看来，登录是基于Ajax完成的；这有一些含义：Ajax需要启用JavaScript(默认为HtmlUnit)

Ajax是异步的-HtmlUnit中的所有操作(例如，单击)都是同步的，这意味着您必须等待ajax调用完成

在您的特殊情况下，ajax调用会通过使用不同的URL(document.location ='main.html')重新加载页面来成功更改页面的内容。因此，您必须刷新页面变量

或在代码中：

try (WebClient webClient = new WebClient(BrowserVersion.FIREFOX_52))

{

webClient.getOptions().setUseInsecureSSL(true);

HtmlPage page = webClient.getPage(url);

String pageContent = page.asText();

System.out.println(pageContent);

HtmlButtonInput button = page.getFirstByXPath("//input[@type = 'button']");

// to make sure you got the right element

System.out.println(button.asXml());

HtmlTextInput name  = (HtmlTextInput) page.getElementById("username");

HtmlPasswordInput pwd  = (HtmlPasswordInput) page.getElementById("password");

// use type() to simulate typing

name.type(username);

pwd.type(password);

// no need to get the page here because this is still the one the

// button is placed on

button.click();

// wait for ajax to do the job

webClient.waitForBackgroundJavaScript(10000);

// ok hopefully the job is done and the login was successfull

// lets get the current page out of the current window

HtmlPage loggedInPage = (HtmlPage) page.getEnclosingWindow().getTopWindow().getEnclosedPage();

...

// check the result

// you can also write this to a file and open it in a real browser

// maybe the login was failing and there is an error message

// rendered on this page

System.out.println(loggedInPage.asXml());

}

希望能有所帮助。