B. Game with Telephone Numbers Educational Codeforces Round 63 (Rated for Div. 2)

题意：

给定字符串，两人游戏轮流删除一个字符，谁先让字符串长度为11且第一个是8即获胜。问先手是否必胜。

思路：0到n-10之间的8的数量大于可移除的数量/2即YES否则NO

参考代码：

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<iostream>
#include<cmath>
#define lson l,mid,root<<1
#define rson mid+1,r,root<<1|1
#define ll long long
const int inf = 0x3f3f3f3f;
const int N=1000000+1;
using namespace std;
int main()
{int n;cin>>n;string a;cin>>a;int num=n-10;int id=0;for(int i=0;i<num;i++){if(a[i]=='8')id++;}if(id>num/2)printf("YES\n");elseprintf("NO\n");return 0;
}

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B. Game with Telephone Numbers Educational Codeforces Round 63 (Rated for Div. 2)

题意：

给定字符串，两人游戏轮流删除一个字符，谁先让字符串长度为11且第一个是8即获胜。问先手是否必胜。

思路：0到n-10之间的8的数量大于可移除的数量/2即YES否则NO

参考代码：

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