Input

    输入一个整数T(T<=20)，表示教练员有几次测试。接下来3行，第一行为一个整数W，表示该信号源是属于哪个波段，2或80。第二、三行为一串摩斯密码，长度不超过90，表示BM听到的两个信号源对应的信号。

Output

    每组数据输出一行，输出两个信号源对应数字之和在相应波段下的摩斯密码。

#include<stdio.h>
#include<string.h>typedef struct {int flag;int len;char chunk[12];
}present[10];present sale2, sale80;void Traverse()
{int i;for(i=0; i<10; ++i) {sale2[i].flag = i; sale2[i].len = 5;}strcpy(sale2[0].chunk , "-----");    strcpy(sale2[1].chunk , ".----");strcpy(sale2[2].chunk , "..---");    strcpy(sale2[3].chunk , "...--");strcpy(sale2[4].chunk , "....-");    strcpy(sale2[5].chunk , ".....");strcpy(sale2[6].chunk , "-....");    strcpy(sale2[7].chunk , "--...");strcpy(sale2[8].chunk , "---..");    strcpy(sale2[9].chunk , "----.");sale80[0].flag = 5; strcpy(sale80[0].chunk , "-- ---....."); sale80[0].len = 11;sale80[1].flag = 4; strcpy(sale80[1].chunk , "-- ---...."); sale80[1].len = 10;sale80[2].flag = 3; strcpy(sale80[2].chunk , "-- ---..."); sale80[2].len = 9;sale80[3].flag = 2; strcpy(sale80[3].chunk , "-- ---.."); sale80[3].len = 8;sale80[4].flag = 1; strcpy(sale80[4].chunk , "-- ---."); sale80[4].len = 7;sale80[5].flag = 0; strcpy(sale80[5].chunk , "-----"); sale80[5].len = 5;sale80[6].flag = 6; strcpy(sale80[6].chunk , "-...."); sale80[6].len = 5;sale80[7].flag = 7; strcpy(sale80[7].chunk , "--..."); sale80[7].len = 5;sale80[8].flag = 8; strcpy(sale80[8].chunk , "---.."); sale80[8].len = 5;sale80[9].flag = 9; strcpy(sale80[9].chunk , "----."); sale80[9].len = 5;return;
}int main()
{int a[20], b[20], sum[20];int sel, i, j, T, s1len, s2len, s1cnt, s2cnt, temp, e, len, flag;char s1[100], s2[100], *str;Traverse();scanf("%d", &T);while(T--){memset(a, 0, sizeof(a));memset(b, 0, sizeof(b));memset(sum, 0, sizeof(sum));memset(s1, 0, sizeof(s1));memset(s2, 0, sizeof(s2));s2len = s1len = s1cnt = s2cnt = flag = 0;scanf("%d", &sel);getchar();  //这里有一个回车，而fgets会吸收回车 //scanf("%s", s1);fgets(s1, 100, stdin);fgets(s2, 100, stdin);//scanf("%s", s2);s1len = strlen(s1)-1, s2len = strlen(s2)-1;if(sel == 2){for(i=0, str=s1; i<s1len; ){for(j=0; j<10; ++j){if(str == strstr(str, sale2[j].chunk)){i += sale2[j].len;a[s1cnt++] = sale2[j].flag;str = s1+i;break;}}}for(i=0, str=s2; i<s2len; ){for(j=0; j<10; ++j){if(str == strstr(str, sale2[j].chunk)){i += sale2[j].len;b[s2cnt++] = sale2[j].flag;str = s2+i;break;}}}}else {for(i=0, str=s1; i<s1len; ){for(j=0; j<10; ++j){if(str == strstr(str, sale80[j].chunk)){i += sale80[j].len;a[s1cnt++] = sale80[j].flag;str = s1+i;break;}}}for(i=0,str=s2; i<s2len; ){for(j=0; j<10; ++j){if(str == strstr(str, sale80[j].chunk)){i += sale80[j].len;b[s2cnt++] = sale80[j].flag;str = s2+i;break;}}}}for(i=0, j=s1cnt-1; i<j; ++i, --j) {temp = a[i]; a[i] = a[j]; a[j] = temp;} for(i=0, j=s2cnt-1; i<j; ++i, --j) {temp = b[i]; b[i] = b[j]; b[j] = temp;} //    for(i=0; i<s1cnt; ++i) {printf("a[%d] = %d\n", i, a[i]);} //    for(i=0; i<s2cnt; ++i) {printf("b[%d] = %d\n", i, b[i]);}
        len = s1cnt<s2cnt ? s1cnt:s2cnt;for(i=0, e=0; i<len; ++i){temp = (e + a[i] + b[i]);sum[i] = temp%10;e = temp/10;}if(i < s1cnt)while(i != s1cnt){temp = e + a[i] + sum[i];sum[i] = temp%10;e = temp/10;i++;}else while(i != s2cnt){temp = e + b[i] + sum[i];sum[i] = temp%10;e = temp/10;i++;}for(; i<20 && e; ++i) {temp = e + sum[i];sum[i] = temp%10;e = temp/10;}for(i=20-1; i>0 && !sum[i]; --i);for(; i>=0; --i) {//    printf("%d", sum[i]);if(sel == 2) printf("%s", sale2[sum[i]].chunk);else {if(sum[i]>=6)printf("%s", sale80[sum[i]].chunk);else printf("%s", sale80[5 - sum[i]].chunk);}}printf("\n"); }return 0;
}