Codeforces--839A--Arya and Bran

题目
Bran and his older sister Arya are from the same house. Bran like candies so much, so Arya is going to give him some Candies.

At first, Arya and Bran have 0 Candies. There are n days, at the i-th day, Arya finds ai candies in a box, that is given by the Many-Faced God. Every day she can give Bran at most 8 of her candies. If she don’t give him the candies at the same day, they are saved for her and she can give them to him later.

Your task is to find the minimum number of days Arya needs to give Bran k candies before the end of the n-th day. Formally, you need to output the minimum day index to the end of which k candies will be given out (the days are indexed from 1 to n).

Print -1 if she can’t give him k candies during n given days.

Input
The first line contains two integers n and k (1 ≤ n ≤ 100, 1 ≤ k ≤ 10000).

The second line contains n integers a1, a2, a3, …, an (1 ≤ ai ≤ 100).

Output
If it is impossible for Arya to give Bran k candies within n days, print -1.

Otherwise print a single integer — the minimum number of days Arya needs to give Bran k candies before the end of the n-th day.

Example
Input
2 3
1 2
Output
2
Input
3 17
10 10 10
Output
3
Input
1 9
10
Output
-1
Note
In the first sample, Arya can give Bran 3 candies in 2 days.

In the second sample, Arya can give Bran 17 candies in 3 days, because she can give him at most 8 candies per day.

In the third sample, Arya can’t give Bran 9 candies, because she can give him at most 8 candies per day and she must give him the candies within 1 day.

这道题目需要注意思路：
首先是要判断当天的糖果是不是>8的，大于8就减8，并将多于糖果留给下一天，小于就减本身数量。最后通过判断是否能在规定的天数里面完成。
见代码：

#include<cstdio>
int a[105];
int main()
{int n,k,i,cnt=0,num=0;scanf("%d%d",&n,&k);{for(i=0;i<n;i++)scanf("%d",&a[i]);for(i=0;i<n;i++){cnt++;num=num+a[i];if(num>8){k=k-8;num=num-8;}else{k=k-num;num=0;}if(k<=0)break;}if(i==n)cnt=-1;printf("%d\n",cnt);}return 0;
}

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