[Linked List]Intersection of Two Linked Lists
Write a program to find the node at which the intersection of two singly linked lists begins.
For example, the following two linked lists:
A: a1 → a2↘c1 → c2 → c3↗ B: b1 → b2 → b3
begin to intersect at node c1.
Notes:
- If the two linked lists have no intersection at all, return
null. - The linked lists must retain their original structure after the function returns.
- You may assume there are no cycles anywhere in the entire linked structure.
- Your code should preferably run in O(n) time and use only O(1) memory.
/*** Definition for singly-linked list.* struct ListNode {* int val;* ListNode *next;* ListNode(int x) : val(x), next(NULL) {}* };*/
class Solution {
public:int getListLength(ListNode* head){int len = 0;while(head){len++;head=head->next;}return len;}ListNode *getIntersectionNode(ListNode *headA, ListNode *headB) {int lenA = getListLength(headA);int lenB = getListLength(headB);ListNode* common = NULL,*startA=headA,*startB=headB;if(lenA<lenB){int diff = lenB-lenA;while(diff--) startB=startB->next;}else{int diff = lenA-lenB;while(diff--) startA=startA->next;}while(startA){if(startA == startB){common = startA;break;}startA=startA->next;startB=startB->next;}return common;}
};转载于:https://www.cnblogs.com/zengzy/p/5041278.html
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