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谁能将下面这段代码用matlab实现？

from __future__ import division

import copy

#计算|X|

def ind(samples = []):

#根据每行数据的值进行分组，值和数据条数存在列表number中

number = []

for u in samples:

if len(number) == 0:

number.append([u,1])

else:

flag = 0 #变量flag表示u是否在number中

for i in number:

if i[0] == u:

i[1] = i[1] + 1

flag = 1

if flag ==0:#u不在number中则新添一条记录到number中

number.append([u,1])

X = 0 #X表示|X|

for i in number:

X = X + i[1]*i[1]

return X

#计算单属性重要度，结果保存到列表Sig中

def Sig(samples = []):

Sig = []

for i in range(len(samples[0])):

samplesX = copy.deepcopy(samples)

for u in samplesX:

u.pop(i)

Sig.append(round((1-ind(samples)/ind(samplesX)),2))

return Sig

#用双属性组合方法计算重要度，结果保存到列表Sig2中

def Sig2(samples = []):

Sig = []

Sig2 = []

SigDouble = []#保存双属性组合重要度

for i in range(len(samples[0])):

samplesX = copy.deepcopy(samples)

SigDouble.append([])

for u in samplesX:

u.pop(i)

Sig.append(round((1-ind(samples)/ind(samplesX)),2)) #计算单属性重要度

for j in range(len(samplesX[0])):

samplesY = copy.deepcopy(samplesX)

for u in samplesY:

u.pop(j)

SigDouble[i].append(round(( 1-ind(samples)/ind(samplesY)),2))

for i in range(len(Sig)):

sum_SigDouble = 0

for j in SigDouble[i]:

sum_SigDouble = sum_SigDouble + (j-Sig[i])

Sig2.append(round(abs((Sig[i]-sum_SigDouble/2/3)),3))

print Sig,SigDouble,Sig2

return Sig2

#计算各属性客观权重,结果保存到列表P中

def P(Sig = []):

P = []

sum_Sig = 0

for i in Sig:

sum_Sig = sum_Sig + i

for i in Sig:

P.append(round(i/sum_Sig,3))

return P

samples = []

for line in open(*samples.txt*):

u = line.strip(*\n*).split(*\t*) #去掉换行符，用tab分割字符

samples.append(u) #获得完整样本

#去掉决策属性

n = len(samples[0])

for u in samples:

u.pop(n-1)

print u*属性客观权重：*

print P(Sig(samples))

print u*双属性组合方法客观权重：*

print P(Sig2(samples))