892A Greed

很简单，但是注意会超int 范围~

                        A. Greedtime limit per test2 secondsmemory limit per test256 megabytesinputstandard inputoutputstandard output

Jafar has n cans of cola. Each can is described by two integers: remaining volume of cola ai and can’s capacity bi (ai ≤ bi).

Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not!

Input
The first line of the input contains one integer n (2 ≤ n ≤ 100 000) — number of cola cans.

The second line contains n space-separated integers a1, a2, …, an (0 ≤ ai ≤ 109) — volume of remaining cola in cans.

The third line contains n space-separated integers that b1, b2, …, bn (ai ≤ bi ≤ 109) — capacities of the cans.

Output
Print “YES” (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print “NO” (without quotes).

You can print each letter in any case (upper or lower).

Examples
input
2
3 5
3 6
output
YES
input
3
6 8 9
6 10 12
output
NO
input
5
0 0 5 0 0
1 1 8 10 5
output
YES
input
4
4 1 0 3
5 2 2 3
output
YES
Note
In the first sample, there are already 2 cans, so the answer is “YES”.

#include<cstdio>
#include<iostream>
#include<algorithm>
using namespace std;
const int N=1e5+10;
int a[N],b[N];
bool cmp(int a,int b)
{
return a>b;
}
int main()
{
long long n,sum;
while(cin>>n)
{sum=0;for(int i=0; i<n; i++){cin>>a[i];sum+=a[i];}for(int i=0; i<n; i++)cin>>b[i];sort(b,b+n,cmp);if(sum<=b[0]+b[1])puts("YES");else puts("NO");}
return 0;

}

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