Python爬取必应壁纸的代码实例

本篇文章小编给大家分享一下Python爬取必应壁纸的代码实例，小编觉得挺不错的，现在分享给大家供大家参考，有需要的小伙伴们可以来看看。

代码如下：

import re

import os

import requests

from time import sleep

headers = {

"User-Agent": ("Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:64.0) "

"Gecko/20100101 Firefox/64.0")

}

def get_index(resolution, index=1):

url = f"https://bing.ioliu.cn/ranking?p={index}"

res = requests.get(url, headers=headers)

urls = re.findall('pic=(.*?)\\.jpg', res.text)

_old_resolution = urls[1].split("_")[-1]

return {url.split("/")[-1].replace(_old_resolution, resolution): url.replace(_old_resolution, resolution) + ".jpg"

for url in urls}

def download_pic(pics):

if os.path.exists('F:\\必应壁纸'):

pass

else:

os.mkdir('F:\\必应壁纸')

print('目录创建成功')

try:

for pic_name, pic_url in pics.items():

res = requests.get(pic_url, headers=headers)

with open(f"F:\\必应壁纸\\{pic_name}.jpg", mode="wb") as f:

f.write(res.content)

print(f"{pic_name} 下载完成")

except Exception as e:

print("下载出错", e)

def input_index():

print("必应壁纸下载工具, 本工具未经资源站授权.")

print("仅做学习和交流之用, 随时有可能停止维护.")

print("目前资源站收容页数为87,当前仅提供1920x1080分辨率下载")

while True:

sleep(0.1)

index = input("请输入要下载的页数(Max=87):")

try:

if index == "Q":

exit()

index = 87 if int(index) > 87 else int(index)

return index

except ValueError:

print("请输入数字, 或输入Q退出!")

def main():

index = input_index()

i = 1

while i <= index:

print(f"当前第{i}页,共需要下载{index}页")

pics = get_index("1920x1080", i)

download_pic(pics)

i += 1

print("下载完成,将在3秒后关闭...")

sleep(1)

print("2")

sleep(1)

print("1")

sleep(1)

print("0")

if __name__ == '__main__':

main()

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