这将允许您迭代行。它的一部分是从我在answer中找到的一些代码派生出来的。

在这个时间点(pylzma-0.5.0)上，py7zlib模块没有实现允许存档成员作为字节流或字符流读取的API，它的ArchiveFile类只提供一个read()函数，该函数一次解压缩并返回成员中的未压缩数据。考虑到这一点，最好的方法是通过Python生成器将字节或行作为缓冲区迭代返回。

下面是后者，但如果问题是存档成员文件本身太大，则可能没有帮助。

下面的代码应该可以在Python3.x和2.7中使用。import io

import os

import py7zlib

class SevenZFileError(py7zlib.ArchiveError):

pass

class SevenZFile(object):

@classmethod

def is_7zfile(cls, filepath):

""" Determine if filepath points to a valid 7z archive. """

is7z = False

fp = None

try:

fp = open(filepath, 'rb')

archive = py7zlib.Archive7z(fp)

_ = len(archive.getnames())

is7z = True

finally:

if fp: fp.close()

return is7z

def __init__(self, filepath):

fp = open(filepath, 'rb')

self.filepath = filepath

self.archive = py7zlib.Archive7z(fp)

def __contains__(self, name):

return name in self.archive.getnames()

def readlines(self, name, newline=''):

r""" Iterator of lines from named archive member.

`newline` controls how line endings are handled.

It can be None, '', '\n', '\r', and '\r\n' and works the same way as it does

in StringIO. Note however that the default value is different and is to enable

universal newlines mode, but line endings are returned untranslated.

"""

archivefile = self.archive.getmember(name)

if not archivefile:

raise SevenZFileError('archive member %r not found in %r' %

(name, self.filepath))

# Decompress entire member and return its contents iteratively.

data = archivefile.read().decode()

for line in io.StringIO(data, newline=newline):

yield line

if __name__ == '__main__':

import csv

if SevenZFile.is_7zfile('testing.csv.7z'):

sevenZfile = SevenZFile('testing.csv.7z')

if 'testing.csv' not in sevenZfile:

print('testing.csv is not a member of testing.csv.7z')

else:

reader = csv.reader(sevenZfile.readlines('testing.csv'))

for row in reader:

print(', '.join(row))