1 //树链剖分 点权修改 修改单节点
  2 #include <iostream>
  3 #include <cstring>
  4 #include <algorithm>
  5 #include <cstdio>
  6 using namespace std;
  7 const int MAXN = 3e4 + 10;
  8 struct data {
  9     int to , next;
 10 }edge[MAXN << 1];
 11 int head[MAXN] , cnt , tot;
 12 int top[MAXN] , par[MAXN] , son[MAXN] , size[MAXN] , dep[MAXN];
 13 int id[MAXN] , fid[MAXN]; //id[i]表示i对应在线段树上的位置 fid[i]表示线段树位置是i的叶子 对应的节点
 14 int a[MAXN];
 15
 16 void init() {
 17     tot = cnt = 0;
 18     memset(head , -1 , sizeof(head));
 19 }
 20
 21 inline void add(int u , int v) {
 22     edge[tot].next = head[u];
 23     edge[tot].to = v;
 24     head[u] = tot++;
 25 }
 26
 27 void dfs1(int u , int p , int d) {
 28     dep[u] = d , size[u] = 1 , son[u] = u , par[u] = p;
 29     for(int i = head[u] ; ~i ; i = edge[i].next) {
 30         int v = edge[i].to;
 31         if(v == p)
 32             continue;
 33         dfs1(v , u , d + 1);
 34         if(size[v] >= size[son[u]] || son[u] == u)
 35             son[u] = v;
 36         size[u] += size[v];
 37     }
 38 }
 39
 40 void dfs2(int u , int p , int t) {
 41     top[u] = t , id[u] = ++cnt;
 42     fid[cnt] = u;
 43     if(son[u] != u)
 44         dfs2(son[u] , u , t);
 45     for(int i = head[u] ; ~i ; i = edge[i].next) {
 46         int v = edge[i].to;
 47         if(v == p || v == son[u])
 48             continue;
 49         dfs2(v , u , v);
 50     }
 51 }
 52
 53 struct segtree {
 54     int l , r;
 55     int sum , Max;
 56 }T[MAXN << 2];
 57
 58 void build(int p , int l , int r) {
 59     int mid = (l + r) >> 1;
 60     T[p].l = l , T[p].r = r;
 61     if(l == r) {
 62         T[p].Max = T[p].sum = a[fid[l]]; //
 63         return ;
 64     }
 65     build(p << 1 , l , mid);
 66     build((p << 1)|1 , mid + 1 , r);
 67     T[p].sum = T[p << 1].sum + T[(p << 1)|1].sum;
 68     T[p].Max = max(T[p << 1].Max , T[(p << 1)|1].Max);
 69 }
 70
 71 void updata(int p , int pos , int num) {
 72     int mid = (T[p].l + T[p].r) >> 1;
 73     if(T[p].l == T[p].r && T[p].l == pos) {
 74         T[p].sum = T[p].Max = num;
 75         return ;
 76     }
 77     if(pos <= mid) {
 78         updata(p << 1 , pos , num);
 79     }
 80     else {
 81         updata((p << 1)|1 , pos , num);
 82     }
 83     T[p].sum = T[p << 1].sum + T[(p << 1)|1].sum;
 84     T[p].Max = max(T[p << 1].Max , T[(p << 1)|1].Max);
 85 }
 86
 87 int query_sum(int p , int l , int r) {
 88     int mid = (T[p].l + T[p].r) >> 1;
 89     if(T[p].l == l && T[p].r == r) {
 90         return T[p].sum;
 91     }
 92     if(r <= mid) {
 93         return query_sum(p << 1 , l , r);
 94     }
 95     else if(l > mid) {
 96         return query_sum((p << 1)|1 , l , r);
 97     }
 98     else {
 99         return query_sum(p << 1 , l , mid) + query_sum((p << 1)|1 , mid + 1 , r);
100     }
101 }
102
103 int query_max(int p , int l , int r) {
104     int mid = (T[p].l + T[p].r) >> 1;
105     if(T[p].l == l && T[p].r == r) {
106         return T[p].Max;
107     }
108     if(r <= mid) {
109         return query_max(p << 1 , l , r);
110     }
111     else if(l > mid) {
112         return query_max((p << 1)|1 , l , r);
113     }
114     else {
115         return max(query_max(p << 1 , l , mid) , query_max((p << 1)|1 , mid + 1 , r));
116     }
117 }
118
119 int find_max(int u , int v) {
120     int fu = top[u] , fv = top[v];
121     int Max = -1000000000;
122     while(fu != fv) {
123         if(dep[fu] >= dep[fv]) {
124             Max = max(Max , query_max(1 , id[fu] , id[u]));
125             u = par[fu];
126             fu = top[u];
127         }
128         else {
129             Max = max(Max , query_max(1 , id[fv] , id[v]));
130             v = par[fv];
131             fv = top[v];
132         }
133     }
134     if(dep[u] >= dep[v]) {
135         return max(Max , query_max(1 , id[v] , id[u]));
136     }
137     else {
138         return max(Max , query_max(1 , id[u] , id[v]));
139     }
140 }
141
142 int find_sum(int u , int v) {
143     int fu = top[u] , fv = top[v];
144     int sum = 0;
145     while(fu != fv) {
146         if(dep[fu] > dep[fv]) {
147             sum += query_sum(1 , id[fu] , id[u]);
148             u = par[fu];
149             fu = top[u];
150         }
151         else {
152             sum += query_sum(1 , id[fv] , id[v]);
153             v = par[fv];
154             fv = top[v];
155         }
156     }
157     if(dep[u] >= dep[v]) {
158         return (sum + query_sum(1 , id[v] , id[u]));
159     }
160     else {
161         return (sum + query_sum(1 , id[u] , id[v]));
162     }
163 }
164
165 int main()
166 {
167     int n , u , v;
168     while(~scanf("%d" , &n)) {
169         init();
170         for(int i = 1 ; i < n ; ++i) {
171             scanf("%d %d" , &u , &v);
172             add(u , v);
173             add(v , u);
174         }
175         for(int i = 1 ; i <= n ; ++i) {
176             scanf("%d" , a + i);
177         }
178         cnt = 0;
179         dfs1(1 , 1 , 0);
180         dfs2(1 , 1 , 1);
181         build(1 , 1 , cnt);
182         int m;
183         char q[10];
184         scanf("%d" , &m);
185         while(m--) {
186             scanf("%s%d%d" , q , &u , &v);
187             if(q[0] == 'C') {
188                 updata(1 , id[u] , v);
189             }
190             else if(strcmp(q ,"QMAX") == 0) {
191                 printf("%d\n" , find_max(u , v));
192             }
193             else {
194                 printf("%d\n", find_sum(u , v));
195             }
196         }
197     }
198     return 0;
199 }