英文文档：oct ( x )

Convert an integer number to an octal string. The result is a valid Python expression. If x is not a Pythonobject,

it has to define anmethod that returns an integer.

说明：

1. 函数功能将一个整数转换成8进制字符串。如果传入浮点数或者字符串均会报错。>>> a = oct(10)

>>> a

'0o12'

>>> type(a) # 返回结果类型是字符串

>>> oct(10.0) # 浮点数不能转换成8进制

Traceback (most recent call last):

File "", line 1, in

oct(10.0)

TypeError: 'float' object cannot be interpreted as an integer

>>> oct('10') # 字符串不能转换成8进制

Traceback (most recent call last):

File "", line 1, in

oct('10')

TypeError: 'str' object cannot be interpreted as an integer

2. 如果传入参数不是整数，则其必须是一个定义了__index__并返回整数函数的类的实例对象。

# 未定义__index__函数，不能转换

>>> class Student:

def __init__(self,name,age):

self.name = name

self.age = age

>>> a = Student('Kim',10)

>>> oct(a)

Traceback (most recent call last):

File "", line 1, in

oct(a)

TypeError: 'Student' object cannot be interpreted as an integer

# 定义了__index__函数，但是返回值不是int类型，不能转换>>> class Student:

def __init__(self,name,age):

self.name = name

self.age = age

def __index__(self):

return self.name

>>> a = Student('Kim',10)

>>> oct(a)

Traceback (most recent call last):

File "", line 1, in

oct(a)

TypeError: __index__ returned non-int (type str)

# 定义了__index__函数，而且返回值是int类型，能转换

>>> class Student:

def __init__(self,name,age):

self.name = name

self.age = age

def __index__(self):

return self.age

>>> a = Student('Kim',10)

>>> oct(a)

'0o12'

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TAG标签：OCT函数