想到map了,可惜没想到用erase来节省空间,看了网上答案

 1 class Solution {
 2 public:
 3     int longestConsecutive(vector<int> &num) {
 4         // Start typing your C/C++ solution below
 5         // DO NOT write int main() function
 6         map<int, int> rec;
 7         for (int i = 0; i < num.size(); i++) rec.insert(pair<int, int>(num[i], 1));
 8         int maxcon = 0;
 9         for (int i = 0; i < num.size(); i++) {
10             map<int, int>::iterator it = rec.find(num[i]);
11             if (it != rec.end()) {
12                 int left = num[i]-1;
13                 int right = num[i]+1;
14                 while (1) {
15                     map<int, int>::iterator iter = rec.find(left);
16                     if (iter != rec.end()) {
17                         left--;
18                         rec.erase(iter);
19                     }
20                     else break;
21                 }
22                 left++;
23                 while (1) {
24                     map<int, int>::iterator iter = rec.find(right);
25                     if (iter != rec. end()) {
26                         right++;
27                         rec.erase(iter);
28                     }
29                     else break;
30                 }
31                 right--;
32                 maxcon = max(maxcon, right - left + 1);
33                 rec.erase(it);
34             }
35         }
36         return maxcon;
37     }
38 };

贴上自己写的更加简单的代码

 1 class Solution {
 2 public:
 3     int longestConsecutive(vector<int> &num) {
 4         // Start typing your C/C++ solution below
 5         // DO NOT write int main() function
 6         map<int, int> S;
 7         int sum = 0;
 8         for (int i = 0; i < num.size(); i++) S[num[i]] = 1;
 9         for (int i = 0; i < num.size(); i++) {
10             if (S.count(num[i])) {
11                 int left = 1;
12                 int tmp = num[i];
13                 while (S.count(tmp-left)) {
14                     S.erase(tmp-left);
15                     left++;
16                 }
17                 int right = 1;
18                 while (S.count(tmp+right)) {
19                     S.erase(tmp+right);
20                     right++;
21                 }
22                 S.erase(tmp);
23                 sum = max(sum, left+right-1);
24             }
25         }
26         return sum;
27     }
28 };

C#

 1 public class Solution {
 2     public int LongestConsecutive(int[] nums) {
 3         Dictionary<int, int> S = new Dictionary<int, int>();
 4         int ans = 0;
 5         for (int i = 0; i < nums.Length; i++) {
 6             if (!S.ContainsKey(nums[i])) S.Add(nums[i], 1);
 7         }
 8         for (int i = 0; i < nums.Length; i++) {
 9             if (S.ContainsKey(nums[i])) {
10                 int left = 1;
11                 int tmp = nums[i];
12                 while (S.ContainsKey(tmp - left)) {
13                     S.Remove(tmp - left);
14                     left++;
15                 }
16                 int right = 1;
17                 while (S.ContainsKey(tmp + right)) {
18                     S.Remove(tmp + right);
19                     right++;
20                 }
21                 S.Remove(tmp);
22                 ans = Math.Max(ans, left + right - 1);
23             }
24         }
25         return ans;
26     }
27 }

View Code

转载于:https://www.cnblogs.com/yingzhongwen/archive/2013/04/02/2995933.html

LeetCode: Longest Consecutive Sequence相关推荐

  1. LeetCode: Longest Consecutive Sequence [128]

    [题目] Given an unsorted array of integers, find the length of the longest consecutive elements sequen ...

  2. LeetCode:Longest Consecutive Sequence

    题目链接 Given an unsorted array of integers, find the length of the longest consecutive elements sequen ...

  3. [LeetCode] Longest Consecutive Sequence 求解

    为什么80%的码农都做不了架构师?>>>    题目 Given an unsorted array of integers, find the length of the long ...

  4. leetcode Longest Consecutive Sequence

    #include <iostream> #include <vector> #include <unordered_map>// 时间复杂度是O(n), 空间复杂度 ...

  5. [leetcode]Longest Consecutive Sequence

    这道题目一看就去翻答案了,因为以前见过,知道并查集可以用来做分组,但这样的题目真的要并查集么?想想也是HashSet之类就能搞定么.果然是HashMap而不是HashSet.下面这个解法我比较容易理解 ...

  6. 298. Binary Tree Longest Consecutive Sequence

    题目: Given a binary tree, find the length of the longest consecutive sequence path. The path refers t ...

  7. leetcode 128. Longest Consecutive Sequence | 128. 最长连续序列(Java)

    题目 https://leetcode.com/problems/longest-consecutive-sequence/ 题解 方法1:HashMap 解法,O(n^2) 如下图,假设 n=4 被 ...

  8. LeetCode 128. 最长连续序列(Longest Consecutive Sequence)

    题目描述 给定一个未排序的整数数组,找出最长连续序列的长度. 要求算法的时间复杂度为 O(n). 示例: 输入: [100, 4, 200, 1, 3, 2] 输出: 4 解释: 最长连续序列是 [1 ...

  9. 128. Longest Consecutive Sequence

    Title 给定一个未排序的整数数组,找出最长连续序列的长度. 要求算法的时间复杂度为 O(n). 示例: 输入: [100, 4, 200, 1, 3, 2] 输出: 4 解释: 最长连续序列是 [ ...

最新文章

  1. java让用户输入3个随机数_3-流程控制、随机数、键盘输入
  2. Java synchronized 和 volatile 的区别
  3. vue 加载时掉用mounted_Vue实例中生命周期created和mounted的区别详解
  4. 第七周实践项目4 队列数组
  5. 深入剖析ASP.NET的编译原理之二:预编译(Precompilation)
  6. 还不知道这 11 个超酷的编程新工具你就 out 了!
  7. csv文件-读取方式、字典
  8. 找不org.apache.commons.lang3.builder.EqualsBuilder和commons-lang下载链接
  9. VUE中友盟统计的使用方法
  10. springboot启动报错The Bean Validation API is on the classpath but no implementation could be found
  11. What?校花居然半夜问我要“软件”
  12. springboot整合tk-mybatis框架搭建
  13. maven阿里云中央仓库
  14. Zookeeper基础笔记——从小白到入门
  15. IE8允许ActiveX控件设置
  16. 用DOCKER安装及使用SSCHA
  17. 直播带货系统,带货直播系统中发布商品的逻辑处理流程
  18. 线状图斑的平均宽计算
  19. 计算机网络毕业实训报告书,计算机网络实训报告书
  20. 拓嘉辰丰:多多买菜提货点怎样获益?为什么很便宜?

热门文章

  1. 学生上课睡觉班主任怎么处理_学生上课睡觉,老师的管与不管,不是你看到的那么简单...
  2. 规范的 Commit Message
  3. 2022-2028年中国电容器电子薄膜行业市场研究及前瞻分析报告
  4. 2022-2028年中国镀金属膜行业市场研究及前瞻分析报告
  5. LeetCode简单题之构造矩形
  6. relay.build调用关系
  7. 2021 年音视频技术与发展
  8. matrix_multiply代码解析
  9. 蓝牙mesh网络技术的亮点
  10. 机器人导航两篇顶级会议论文解析