BigDecimal num = new BigDecimal("100.000");BigDecimal numNoEndZero = num.stripTrailingZeros();  //numNoEndZero  ：1E+2System.out.println(numNoEndZero.toString());

 String numNoEndZeroStr = new BigDecimal("100.000").stripTrailingZeros().toPlainString();   //numNoEndZeroStr  ：100System.out.println(numNoEndZeroStr);

/*** @Title: clearNoUseZeroForBigDecimal* @Description: 去掉BigDecimal尾部多余的0，通过stripTrailingZeros().toPlainString()实现* @param num* @return BigDecimal*/public static BigDecimal clearNoUseZeroForBigDecimal(BigDecimal num) {BigDecimal returnNum = null;String numStr = num.stripTrailingZeros().toPlainString();if (numStr.indexOf(".") == -1) {// 如果num 不含有小数点,使用stripTrailingZeros()处理时,变成了科学计数法returnNum = new BigDecimal(numStr);} else {if (num.compareTo(BigDecimal.ZERO) == 0) {returnNum = BigDecimal.ZERO;} else {returnNum = num.stripTrailingZeros();}}return returnNum;}

    /*** @Title: removeAmtLastZero* @Description: 金额处理，去掉BigDecimal尾部多余的0* @param num* @return BigDecimal*/public static BigDecimal removeAmtLastZero(BigDecimal num) {String strNum = num.toString();if (strNum.indexOf('.') != -1) {String[] arr = strNum.split("\\.");String strDecimals = arr[1];List<String> list = new ArrayList<String>();boolean isCanAdd = false;for (int i = strDecimals.length() - 1; i > -1; i--) {String ss = String.valueOf(strDecimals.charAt(i));if (!ss.equals("0")) {isCanAdd = true;// 从最后的字符开始算起，遇到第一个不是0的字符开始都是需要保留的字符
                }if (!ss.equals("0") || isCanAdd) {list.add(ss);}}StringBuffer strZero = new StringBuffer();for (int i = list.size() - 1; i > -1; i--) {strZero.append(list.get(i));}strNum = String.format("%s.%s", arr[0], strZero.toString());}return new BigDecimal(strNum);}