在python中不可能轻松地获取变量的名称(请参见answer)。对于在python中传递给函数的变量，有使用inspect、详细信息here和基于此answer的案例解决方案的复杂解决方案import matplotlib.pyplot as plt

import numpy as np

import inspect

import re

def comparigraphside(rawvariable, filtervariable, cut):

calling_frame_record = inspect.stack()[1]

frame = inspect.getframeinfo(calling_frame_record[0])

m = re.search( "comparigraphside\((.+)\)", frame.code_context[0])

if m:

rawvariablename = m.group(1).split(',')[0]

variable = rawvariable[filtervariable > 0]

filtervariable = filtervariable[filtervariable > 0]

upperbound = np.mean(variable) + 3*np.std(variable)

plt.figure(figsize=(20,5))

plt.subplot(121)

plt.hist(variable[filtervariable <= cut], bins=20, range=(0,upperbound), normed=True)

title = "%s customers with %s less than or equal to %s" % (len(variable[filtervariable <= cut]), rawvariablename, cut)

plt.title(title)

plt.subplot(122)

plt.hist(variable[filtervariable > cut], bins=20, range=(0,upperbound), normed=True)

plt.title("%s customers with %s greater than %s" % (len(variable[filtervariable > cut]), rawvariablename, cut));

#A solution using inspect

normdist = np.random.randn(1000)

randdist = np.random.rand(1000)

comparigraphside(normdist, normdist, 0.7)

plt.show()

comparigraphside(randdist, normdist, 0.7)

plt.show()

但是，另一种可能的solution，在您的情况下可能更简洁，就是在函数中使用**kwargs，然后在命令行上定义的变量名将是打印的内容，例如import matplotlib.pyplot as plt

import numpy as np

normdist = np.random.randn(1000)

randdist = np.random.rand(1000)

#Another solution using kwargs

def print_fns(**kwargs):

for name, value in kwargs.items():

plt.hist(value)

plt.title(name)

print_fns(normal_distribution=normdist)

plt.show()

print_fns(random_distribution=randdist)

plt.show()

就我个人而言，除了一个快速绘图脚本之外，我会定义一个包含所有要绘图变量的字典，并为每个变量命名，然后将其传递到函数中。这是更明确的，并确保您没有问题，如果您使用这个绘图作为一个更大的代码的一部分。。。