package com.cn.net;public class test {/*** @param args* @throws InterruptedException */public static void main(String[] args) throws InterruptedException {// TODO Auto-generated method stub//线程Afinal Thread ThreadA = new Thread(new Runnable() {@Overridepublic void run() {for (int i = 0; i < 10; i++){System.out.println("A : " );if (i == 9){break;}try {Thread.sleep(1000);} catch (InterruptedException e) {// TODO Auto-generated catch blocke.printStackTrace();}}}});Thread ThreadB = new Thread(new Runnable()  {@Overridepublic void run() {for (int i = 0; i < 5; i++){System.out.println("B : ");if (i == 4){break;}try {Thread.sleep(1000);} catch (InterruptedException e) {// TODO Auto-generated catch blocke.printStackTrace();}}//                    try {
//                      ThreadA.join();//在这里插入线程A
//                  } catch (InterruptedException e) {
//                      // TODO Auto-generated catch block
//                      e.printStackTrace();
//                  }for (int i = 0; i < 5; i++){System.out.println("C : " );if (i == 4){break;}try {Thread.sleep(1000);} catch (InterruptedException e) {// TODO Auto-generated catch blocke.printStackTrace();}}}});ThreadA.start();ThreadB.start();}}

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading;namespace Mutiprocess
{class Program{static void Main(string[] args){//线程AThread ThreadA = new Thread(delegate(){for (int i = 0; i < 10; i++){Console.WriteLine("A : ");if (i == 9){break;}Thread.Sleep(1000);}});//线程BThread ThreadB = new Thread(delegate(){for (int i = 0; i < 5; i++){Console.WriteLine("B : ");if (i == 4){break;}Thread.Sleep(1000);}ThreadA.Join();//在这里插入线程Afor (int i = 0; i < 5; i++){Console.WriteLine("C : ");if (i == 4){break;}Thread.Sleep(1000);}});ThreadA.Start();ThreadB.Start();//            前5秒 A B交替出现，然后A出现5次，C出现5次。//如果注释掉ThreadA.Join()，那么结果是前5秒AB 交替出现 后5秒AC交替出现。//这里我就不再罗嗦了。还是那样线程B中join了线程A只有A执行结束，才可以继续执行线程B中剩下的代码。//join其实就是使异步执行线程转为同步执行。}}
}