Given a list and we have to find the index/position of minimum and maximum elements of a list in Python.

给定一个列表，我们必须在Python中找到列表的最小和最大元素的索引/位置。

Prerequisite:

先决条件：

• Python | min() Method

  Python | min()方法

• Python | max() Method

  Python | max()方法

Example:

例：

    Input:
list = [10, 1, 2, 20, 3, 20]
Output:
Positive of minimum element:  1
Positive of maximum element:  3

Logic:

逻辑：

To find the positions/indexes of minimum and maximum elements of a list, we need to find the maximum and minimum elements of the list – to find the maximum element of the list, we will use max(list) and to find the minimum element of the list, we will use min(list).

要找到列表的最小和最大元素的位置/索引 ，我们需要找到列表的最大和最小元素–要找到列表的最大元素，我们将使用max(list)并找到最小的元素在列表中，我们将使用min(list) 。

And, to get their indexes, we will use list.index(max(list)) and list.index(min(list)).

并且，要获取其索引，我们将使用list.index(max(list))和list.index(min(list)) 。

Program to find the position of min and max elements of a list in Python

程序以查找Python中列表的最小和最大元素的位置

# declare a list of Integers
list = [10, 1, 2, 20, 3, 20]
# min element's position/index
min = list.index (min(list))
# max element's position/index
max = list.index (max(list))
# printing the position/index of min and max elements
print "position of minimum element: ", min
print "position of maximum element: ", max

Output

输出量

    position of minimum element:  1position of maximum element:  3

Explanation:

说明：

• The minimum number of the list is 1 and it is at 1^st position in the list. To get it’s index, we use list.index(min(list)) statement, min(list) returns 1 (as minimum element) and list.index(1) returns the index of 1 from the list. Hence, the position of minimum element is: 1

  列表的最小数目是1，它是在列表1 ^个位置。 为了得到它的索引，我们使用list.index(min(list))语句，min(list)返回1(作为最小元素)， list.index(1)返回列表中的索引1。 因此，最小元素的位置为：1

• The maximum number of the list if 20 and it is two times in the list, first occurrence of 20 is at 3^rd position and the second occurrence of 20 is at 5^th position. Statement max(list) returns the maximum element of the list, which is 20 and the statement list.index(20) returns the index/position of first matched element. Hence, the position of maximum element is: 3

  列表的最大数目，如果20，它是在该列表两次，20的第一次出现是在^第三位置和20的第二次出现在^第 5位置。 语句max(list)返回列表的最大元素，即20，语句list.index(20)返回第一个匹配元素的索引/位置 。 因此，最大元素的位置是：3

翻译自: https://www.includehelp.com/python/find-the-position-of-minimum-and-maximum-elements-of-a-list.aspx