LeetCode Count of Smaller Numbers After Self

2131231

转载于:https://www.cnblogs.com/ZHONGZHENHUA/p/10974609.html

LeetCode Count of Smaller Numbers After Self相关推荐

LeetCode 315. 计算右侧小于当前元素的个数(Count of Smaller Numbers After Self)
题目描述: 给定一个整数数组 nums,按要求返回一个新数组 counts.数组 counts 有该性质: counts[i] 的值是 nums[i] 右侧小于 nums[i] 的元素的数量. 示例 ...
C++版 - 剑指Offer 面试题36：数组中的逆序对及其变形(Leetcode 315. Count of Smaller Numbers After Self)题解
剑指Offer 面试题36:数组中的逆序对题目:在数组中的两个数字,如果前面一个数字大于后面的数字,则这两个数字组成一个逆序对.输入一个数组,求出这个数组中的逆序对的总数. 例如, 在数组{7,5, ...
递归/归并：count of smaller numbers求逆序数
已知数组nums,求新数组count,count[i]代表了在nums[i]右侧且比 nums[i]小的元素个数. 例如: nums = [5, 2, 6, 1], count = [2, 1, 1, ...
315. Count of Smaller Numbers After Self
文章目录 1 题目理解 2 暴力解法 3 分治法 1 题目理解输入:int[] nums 输出:计数的数组int[] counts 规则:counts[i]表示nums中下标大于i,值小于nums[ ...
315. Count of Smaller Numbers After Self 计算右侧小于当前元素的个数
Title 给定一个整数数组 nums,按要求返回一个新数组 counts.数组 counts 有该性质: counts[i] 的值是 nums[i] 右侧小于 nums[i] 的元素的数量. 示例: ...
leetcode 1365. How Many Numbers Are Smaller Than the Current Number（python）
描述 Given the array nums, for each nums[i] find out how many numbers in the array are smaller than it ...
Leetcode 448. Find All Numbers Disappeared in an Array
Leetcode 448. Find All Numbers Disappeared in an Array Add to List Description Submission Solutions ...
LeetCode之Add Two Numbers
LeetCode之Add Two Numbers 题目:You are given two linked lists representing two non-negative numbers. Th ...
LeetCode 445. Add Two Numbers II
LeetCode 445. Add Two Numbers II Solution1:我的答案利用了栈,这样就不用翻转链表了... /*** Definition for singly-linked ...
【注意】LeetCode 2. Add Two Numbers
LeetCode 2. Add Two Numbers 这种沙比提怎么都写不对了??? Solution1:学习这种写法 /*** Definition for singly-linked list. ...

LeetCode Count of Smaller Numbers After Self

LeetCode Count of Smaller Numbers After Self相关推荐

最新文章

热门文章