Oulipo---KMP
Problem DescriptionThe French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book: Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais… Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces. So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap. InputThe first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format: One line with the word W, a string over {'A', 'B', 'C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W). OutputFor every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T. Sample Input3 BAPC BAPC AZA AZAZAZA VERDI AVERDXIVYERDIAN Sample Output1 3 0 |
题目大意:
求在父串中有几个目标串,注意:在父串中上一个与目标串相同的子串可以和下一个与目标串相等的子串共用字符。
AC代码:
#include<stdio.h>
#include<iostream>
#include<cstring>
using namespace std;
const int maxn=10005;
const int maxn1=1000005;
char S[maxn1],T[maxn];
int l1,l2;
int next1[maxn];
void getnext()
{int i=0,j=-1;next1[0]=-1;while(i<l2){if(j==-1||T[i]==T[j]){++i;++j;if(T[i]!=T[j])next1[i]=j;elsenext1[i]=next1[j];}elsej=next1[j];}
}
int kmp()
{int i=0,j=0,t1=0;while(i<=l1&&j<=l2){if(j==-1||S[i]==T[j]){++i;++j;}elsej=next1[j];if(j==l2){ //注意这里是为什么t1++;j=next1[j];}}return t1;
}
int main()
{int t;scanf("%d",&t);while(t--){cin>>T>>S;l1=strlen(S);l2=strlen(T);getnext();cout<<kmp()<<endl;}return 0;
}
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1686
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