C++小游戏扫雷——如何写出一个简易的扫雷

其实很简单，但是这段代码不知道是否有BUG，有的话可以提出，谢谢大家。
all.h函数库

#include "all.h"
using namespace std;
const int flg_xzy[9][2]={{0,0},{0,1},{0,-1},{1,0},{1,1},{1,-1},{-1,0},{-1,1},{-1,-1}};
int ground=0,mp[105][105],n=9,m=9,Set_number=10,number,Ending=0;
//string s1="mode con cols=",s2=" lines=";
bool vis_xzy[105][105],vis[105][105],se[105][105];
int ran(int x){return x<=0?0:(rand()<<16|rand()<<1|(rand()&1))%x;}
void mp_add(int x,int y,int s){mp[x][y]=-1;for(int k=1;k<9;k++)if(flg_xzy[k][0]+x>=0&&flg_xzy[k][0]+x<n&&flg_xzy[k][1]+y>=0&&flg_xzy[k][1]+y<m)if(mp[flg_xzy[k][0]+x][flg_xzy[k][1]+y]^-1) mp[flg_xzy[k][0]+x][flg_xzy[k][1]+y]+=s;
}
void mak_xzy(int X,int Y,int num){memset(mp,0,sizeof(mp));memset(vis_xzy,0,sizeof(vis_xzy));for(int i=0;i<9;i++)if(flg_xzy[i][0]+X>=0&&flg_xzy[i][0]+X<n&&flg_xzy[i][1]+Y>=0&&flg_xzy[i][1]+Y<m)vis_xzy[flg_xzy[i][0]+X][flg_xzy[i][1]+Y]=1;while(num--){int x=rand()%n,y=rand()%m;while(mp[x][y]||vis_xzy[x][y]) x=rand()%n,y=rand()%m;mp_add(x,y,1);}
}
void DFS_xzy(int x,int y,bool C){vis_xzy[x][y]=1;se[x][y]=1;if(vis[x][y]||mp[x][y]==-1) Ending=1;if(mp[x][y]&&C) return;for (int i=1;i<9;i++){int xx=x+flg_xzy[i][0],yy=y+flg_xzy[i][1];if (xx<0||yy<0||xx>=n||yy>=m||vis_xzy[xx][yy]||vis[xx][yy]) continue;DFS_xzy(xx,yy,1);}
}
void change_mp(){setcolor(ground+12);for(int i=0;i<n;i++)for(int j=0;j<m;j++)if(se[i][j]==1){GOTO(i,j*2);if(!mp[i][j]) printf("  ");else printf("%d ",mp[i][j]);}
}
void Lost(){cls();setcolor(ground+12);printf("Lost\n");Sleep(1500);
}
void Win(){cls();setcolor(ground+12);printf("Win\n");Sleep(1500);
}
int Start(){string s;
//  s=s1+ChangeNumToStr(m)+s2+ChangeNumToStr(n);
//  system(s.c_str());setcolor(ground+14);cls();for(int i=1;i<=n;i++){for(int j=1;j<=m;j++) printf("▇");printf("\n");}setcolor(ground+15);GOTO(n,0);printf("   ");GOTO(n,0);printf("%d",number);int x=0,y=0;GOTO(x,2*y);setcolor(ground+10);printf("▇");bool t=0;int Js=number;while(1){char ch=getch();if(ch<0){ch=getch();GOTO(x,y*2);if(se[x][y]){setcolor(ground+12);if(mp[x][y]) printf("%d ",mp[x][y]);else printf("  ");}else if(vis[x][y]) setcolor(ground+15),printf("▇");else setcolor(ground+14),printf("▇");if(ch==75&&y>0) y--;elseif(ch==77&&y<m-1) y++;elseif(ch==72&&x>0) x--;elseif(ch==80&&x<n-1) x++;GOTO(x,y*2);if(se[x][y]){setcolor(160+12);if(mp[x][y]) printf("%d ",mp[x][y]);else printf("  ");}else setcolor(ground+10),printf("▇");}else{GOTO(x,y*2);if(se[x][y]){setcolor(ground+12);if(mp[x][y]) printf("%d ",mp[x][y]);else printf("  ");}else if(vis[x][y]) setcolor(ground+15),printf("▇");else setcolor(ground+14),printf("▇");if((ch=='W'||ch=='w')&&x>0) x--;elseif((ch=='S'||ch=='s')&&x<n-1) x++;elseif((ch=='A'||ch=='a')&&y>0) y--;elseif((ch=='D'||ch=='d')&&y<m-1) y++;elseif(ch==' '){if(!t) t=1,mak_xzy(x,y,Set_number);if(mp[x][y]==-1){Lost();return 0;}else{memset(vis_xzy,0,sizeof(vis_xzy));DFS_xzy(x,y,0);change_mp();if(Ending){Lost();return 0;}}}if(ch=='P'||ch=='p'){GOTO(x,y*2);vis[x][y]=1-vis[x][y];if(mp[x][y]==-1&&vis[x][y]==1) number--;if(mp[x][y]==-1&&vis[x][y]==0) number++;if(vis[x][y]==1) Js--;if(vis[x][y]==0) Js++;if(Js<0) vis[x][y]=1-vis[x][y],Js++;setcolor(ground+15);GOTO(n,0);printf("   ");GOTO(n,0);printf("%d",Js);if(number==0){Win();return 0;}}GOTO(x,y*2);if(se[x][y]){setcolor(160+12);if(mp[x][y]) printf("%d ",mp[x][y]);else printf("  ");}else setcolor(ground+10),printf("▇");}}
}
void Set(){cls();setcolor(ground+15);printf("选择难度\n");printf("0.返回\n");printf("1.初级\n");printf("2.中级\n");printf("3.高级\n");printf("4.自定义\n");char ch=getch();while(ch<'0'||ch>'4') ch=getch(); if(ch=='0') return;if(ch=='1') n=9,m=9,Set_number=10;elseif(ch=='2') n=16,m=16,Set_number=40;elseif(ch=='3') n=16,m=30,Set_number=99;if(ch^'4') return;int nn=0;while(nn<5||nn>25){printf("行数(范围5~25):");cin>>nn;if(nn<5||nn>25) printf("\n重复");}n=nn;int mm=0;while(mm<5||mm>30){printf("列数(范围5~30):");cin>>mm;if(mm<5||mm>30) printf("\n重复");}m=mm;int tt=0;while(tt<=0||tt>25){printf("雷的个数(范围1~%d):",n*m);cin>>tt;if(tt<=0||tt>25) printf("\n重复");}Set_number=tt;
}
int main(){system("title ");char ch;bsrand();while(1){setcolor(ground+12);cls();memset(se,0,sizeof(se));number=Set_number;Ending=0;memset(vis,0,sizeof(vis)); printf("     主菜单\n");printf("   0.退出\n");printf("   1.开始游戏\n");printf("   2.选择难度\n");printf("   空格点击，P标记\n");setcolor(ground+14);printf("   由小威工作室出品，QQ群号：432180340\n"); ch=getch();if(ch=='0') retr();elseif(ch=='1') Start();elseif(ch=='2') Set();}return 0;
}

由小威工作室出品，QQ群号：432180340，群里会有最新的小游戏o( ^ v ^ )o。