array remove java_how to remove array from another array in javascript
可以将文章内容翻译成中文,广告屏蔽插件会导致该功能失效:
问题:
0: {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500, …}
1: {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500, …}
2: {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500, …}
I want to remove 0:{} array in array. how can i remove? and how to find the value of the first item?
回答1:
Since an array's first element is always index 0, you can use Array.prototype.shift which removes the first element:
const array = [{
id: 1553825061863,
name: "Thai Milk Tea",
qty: "1",
total_amount: 9500,
toppings: 500
}, {
id: 1553825061863,
name: "Thai Milk Tea",
qty: "1",
total_amount: 9500,
toppings: 500
}, {
id: 1553825061863,
name: "Thai Milk Tea",
qty: "1",
total_amount: 9500,
toppings: 500
}];
let remainingArray = array;
remainingArray.shift();
console.log(remainingArray);
.as-console-wrapper {
max-height: 100% !important;
top: auto;
}
回答2:
There can be multiple ways of doing that.
let arr = [{id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500}, {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500}, {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500}]
arr.shift();
console.log(arr);
Note: shift() will modify the original array.
let arr = [{id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500}, {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500}, {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500}]
arr.splice(0,1);
console.log(arr);
Note: splice() will modify the original array.
Using slice
let arr = [{id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500}, {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500}, {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500}]
let res = arr.slice(1)
console.log(res);
Using Spread Operator And Destructuring Assignment
let arr = [{id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500}, {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500}, {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500}]
const [,...rest] = arr
console.log(rest);
回答3:
//try this on your console. You can use the shift operator to shift the first element.
//also to remove the last element use pop
>>var myArr = [{id : 1, name: "A"}, {id: 2, name: "B"}, {id:3, name: "C"}];
undefined
>>myArr.shift(0);
{id: 1, name: "A"}
>>myArr
0: {id: 2, name: "B"}
1: {id: 3, name: "C"}
Here is the detailed link about Array.protoType.shift() which removes the first element:
回答4:
the simple way to remove one array index form array using
var ar = ['zero', 'one', 'two', 'three'];
ar.shift(); // returns "zero"
console.log( ar );
if array like this you can delete 0 index using the following command.
var ar = [
{ id: 155382506003, toppings: 500},
{ id: 155382506002, toppings: 100},
{ id: 155382506001, toppings: 200}
];
ar.shift();
console.log( ar );
回答5:
You have an array of Javascript objects. You can remove the first element by:
using shift function, for example:
var first = fruits.shift(); // remove Apple from the front
using splice function, for example - remove an element by index position:
var removedItem = fruits.splice(pos, 1); // this is how to remove an item
you can access value of an element by index, for example:
var first = fruits[0];
you can find value of a field by using foreach, for example:
fruits.forEach(function(item, index, array) {
if (item.id === 1553825061863) {
console.log(item, index);
}
});
回答6:
As I understood from your question that you have something like below that you have to remove Array2 from Array1,
Array1 = 0: {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500, …}
1: {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500, …}
2: {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500, …}
Array2 = 0: {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500, …}
If so just try as below using the filter function.
var data = Array1;
var selectedRows = Array2;
var unSelectedRows = [];
var unSelectedRows = data.filter( function( el ) {
return !selectedRows.includes( el );
} );
You can get the 1 st and 2nd element in unSelectedRows Array.
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