Openjudge1.4答案

#include <stdio.h>
int main()
{long a;scanf("%ld",&a);if(a==0){printf("zero");}else if(a>0){printf("positive");}else {printf("negative");}return 0;
}

#include <stdio.h>
#include<math.h>
int main()
{double a;scanf("%lf",&a);a*=100;a=abs((int)a);a/=100;printf("%.2f",a);return 0;
}

#include <stdio.h>
#include<math.h>
int main()
{int a;scanf("%d",&a);if(a%2==0){printf("even");}else{printf("odd");}
}

#include <stdio.h>
#include<math.h>
int main()
{char a;scanf("%c",&a);if(a%2==0){printf("NO");}else{printf("YES");}
}

#include <stdio.h>
#include<math.h>
int main()
{long long x,y;scanf("%lld %lld",&x,&y);if(x>y){printf(">");}else if(x<y){printf("<");}else if(x==y){printf("=");}
}

#include <stdio.h>
#include<math.h>
int main()
{int x;scanf("%d",&x);if((x/10)>0&&(x/10)<10){printf("1");}else{printf("0");}
}

#include <stdio.h>
#include<math.h>
int main()
{int a,b;scanf("%d %d",&a,&b);if((a>=10)||(b>=20)){printf("1");}else{printf("0");}
}

#include <stdio.h>
#include<math.h>
int main()
{int a;scanf("%d",&a);if((a%3)==0&&(a%5)==0){printf("YES");}else{printf("NO");}
}

#include <stdio.h>
#include<math.h>
int main()
{int a;int count=0,count3=0,count5=0,count7=0;scanf("%d",&a);if((a%3)==0){count++;count3++;}if((a%5)==0){count++;count5++;}if((a%7)==0){count++;count7++;}if(count==3){printf("3 5 7");}else if(count==2){if(count3==0){printf("5 7");}else if(count5==0){printf("3 7");}else if(count7==0){printf("3 5");}}else if(count==1){if(count3==1){printf("3");}else if(count5==1){printf("5");}else if(count7==1){printf("7");}}else if(count==0){printf("n");}
}

#include <stdio.h>
#include<math.h>
int main()
{int a,b;int count=0; scanf("%d %d",&a,&b);if(a<60){count++;}if(b<60){count++;}if(count==1){printf("1");}else{printf("0");}
}

#include <stdio.h>
#include<math.h>
int main()
{int a[3]={3,5,1};int date;scanf("%d",&date);int i;int flag=0;for(i=0;i<3;i++){if(date==a[i]){flag=1;}}if(flag==0){printf("YES");}else if(flag==1){printf("NO");}
}

#include <stdio.h>
#include<math.h>
int main()
{int distance;scanf("%d",&distance);double bike,walk;walk=distance/1.2;bike=50+distance/3.0;if(bike>walk){printf("Walk");}else if(bike<walk){printf("Bike");}else if(walk==bike){printf("All");}
}

#include <stdio.h>
#include<math.h>
int main()
{double x,y;scanf("%lf",&x);if(x<5&&x>=0){y=-x+2.5;}else if(x<10&&x>=5){y=2-1.5*(x-3)*(x-3);}else if(x<20&&x>=10){y=x/2-1.5;}printf("%.3f",y);
}

#include <stdio.h>
#include<math.h>
int main()
{int weight,cost,beyond;char ch;scanf("%d %c",&weight,&ch);if(weight<=1000){cost=8;}else if(weight>1000){//ceil函数：向上取整，且左右两边为浮点数 beyond=(int)ceil((weight-1000)/500.0);cost=8+4*beyond;}if(ch=='y'){cost+=5;}else if(ch=='n'){}printf("%d",cost);
}

#include <stdio.h>
#include<math.h>
int main()
{int a,b,c,max;scanf("%d %d %d",&a,&b,&c);max=a>b?a:b;if(c>max){max=c;}printf("%d",max);
}

#include <stdio.h>
#include<math.h>
int main()
{int a,b,c;int flag=0;scanf("%d %d %d",&a,&b,&c);if((a<b+c)&&(a>abs(b-c))){if((b<a+c)&&(b>abs(a-c))){if((c<a+b)&&(c>abs(b-a))){flag=1;}}}if(flag==1){printf("yes");}else if(flag==0){printf("no");}
}

#include <stdio.h>
#include<math.h>
int main()
{int year;int ch=0;scanf("%d",&year);if(year%4==0){ch=1;if(year%100==0&&year%400!=0){ch=0;}if(year%3200==0){ch=0; }}if(ch==0){printf("N");}else if(ch==1){printf("Y"); }
}

#include <stdio.h>
#include<math.h>
int main()
{int x,y;scanf("%d %d",&x,&y);if(abs(x)<=1&&abs(y)<=1){printf("yes");}else{printf("no");}
}

#include <stdio.h>
#include<math.h>
int main()
{int x,y,result;char ch;scanf("%d %d %c",&x,&y,&ch);if(ch=='+'){result=x+y;}else if(ch=='-'){result=x-y;}else if(ch=='*'){result=x*y;}else if(ch=='/'){if(y==0){printf("Divided by zero!");return 0;}else{result=x/y;}}else{printf("Invalid operator!");return 0;}printf("%d",result);return 0;
}

#include <stdio.h>
#include<math.h>
int main()
{//难点：当deta=0时，x1=x2=-b/(2*a)，此时若b=0，则输出值为-0.00000不正确，应当输出相反值，同理deta<0时； double a,b,c,deta;double x1,x2;scanf("%lf %lf %lf",&a,&b,&c);deta=b*b-4*a*c;if(deta==0){x1=(-b+sqrt(b*b-4*a*c))/(2*a);if(b==0){x1=-x1;}printf("x1=x2=%.5f",x1);}else if(deta>0){x1=(-b+sqrt(b*b-4*a*c))/(2*a);x2=(-b-sqrt(b*b-4*a*c))/(2*a);printf("x1=%.5f;x2=%.5f",x1,x2);}else if(deta<0){x1=-b/(2*a);x2=sqrt(4*a*c-b*b)/(2*a);if(b==0){x1=-x1;}printf("x1=%.5f+%.5fi;x2=%.5f-%.5fi",x1,x2,x1,x2);}
}

#include <stdio.h>
#include<math.h>
int main()
{//注意当完整的苹果为0时的情况不能为负数 int n,x,y,left;scanf("%d %d %d",&n,&x,&y);left=n-ceil(y*1.0/x);if((n-ceil(y*1.0/x))<=0){printf("0");}else{printf("%d",left);}
}

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Openjudge1.4答案

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