我应该创建一个程序,向用户询问一个数字,并接受该数字的阶乘,然后询问他们是否要执行另一个阶乘(Y,N).

它应该像这样工作：

>输入数字以采用阶乘：4

> 4！ = 24

>是否还有一个阶乘(Y,N)？ ?

>重复直到输入N

我的输出是这样的：

>输入数字以采用阶乘：

>“还有其他析因吗？(是,否)？”

> 4！ = 1,无论我输入Y还是N.

这是我的代码：

import java.util.Scanner;

public class factorial

{

public static void main ( String [] args )

{

Scanner input = new Scanner(System.in);

System.out.print("Enter a number you want to take the factorial of: ");

int num = input.nextInt();

int fact = 1;

System.out.printf("%d! = %d

", num, fact, Factorial(num, fact));

}

public static int Factorial(int num, int fact)

{

Scanner input = new Scanner(System.in);

char foo;

System.out.print("Do another factorial (Y,N)?");

foo = input.next().charAt(0);

for (int i = 1; i >= num; i++)

{

fact *= i;

if (foo == 'Y')

{

System.out.print("Do another factorial (Y,N)?");

foo = input.next().charAt(0);

continue;

}

else

{

break;

}

}

return fact;

}

}

更改后：

import java.util.Scanner;

public class factorial

{

public static void main ( String [] args )

{

Scanner input = new Scanner(System.in);

System.out.print("Enter a number you want to take the factorial of: ");

int num = input.nextInt();

int fact = 1;

System.out.printf("%d! = %d

", num, Factorial(num, fact));

System.out.print("Do another factorial (Y,N)? ");

char foo = input.next().charAt(0);

while (foo != 'N')

{

System.out.print("Do another factorial (Y,N)? ");

foo = input.next().charAt(0);

System.out.print("Enter a number you want to take the factorial of: ");

num = input.nextInt();

System.out.printf("%d! = %d

", num, Factorial(num, fact));

}

}

public static int Factorial(int num, int fact)

{

for (int i = 1; i <= num; i++)

{

fact *= i;

}

return fact;

}

}

输出仍然有一些问题：

>输入数字以采用阶乘：4

> 4！ = 24

>是否还有一个阶乘(Y,N)？ ?

>是否还有一个阶乘(Y,N)？ ?

>输入数字以采用阶乘：4

> 4！ = 24

>是否还有一个阶乘(Y,N)？ ?

>输入数字以采用阶乘：