Sqlzoo习题练习：More JOIN operations

下面会涉及到更多连接的概念。数据库由三个表组成：movie , actor 和 casting以及三个表之间的关系。

下面为More JOIN 习题内容：

--#1/*List the films where the yr is 1962 [Show id, title]*/

SELECT id, title

FROM movie

WHERE yr=1962;

--#2/*Give year of 'Citizen Kane'.*/

SELECT yr

FROM movie

WHERE title = 'Citizen Kane';

--#3/*List all of the Star Trek movies, include the id, title and yr (all of these movies include the words Star Trek in the title). Order results by year.*/

SELECT id,title,yr

FROM movie

WHERE title LIKE 'Star Trek%';

--#4/*What id number does the actor 'Glenn Close' have?*/

SELECT id FROM actor

WHERE name = 'Glenn Close';

--#5/*What is the id of the film 'Casablanca'*/

SELECT id

FROM movie

WHERE title = 'Casablanca';

--#6/*Obtain the cast list for 'Casablanca'.what is a cast list?The cast list is the names of the actors who were in the movie.Use movieid=11768, (or whatever value you got from the previous question)*/

SELECT actor.name

FROM actor JOIN casting ON (actor.id=casting.actorid)

WHERE casting.movieid = 11768;

--#7/*Obtain the cast list for the film 'Alien'*/

SELECT actor.name

FROM actor JOIN casting

ON (actor.id=casting.actorid)

JOIN movie

ON (movie.id = casting.movieid)

WHERE movie.title = 'Alien' ;

--#8/*List the films in which 'Harrison Ford' has appeared*/

SELECT movie.title

FROM actor JOIN casting

ON (actor.id=casting.actorid)

JOIN movie

ON (movie.id = casting.movieid)

WHERE actor.name = 'Harrison Ford';

--#9/*List the films where 'Harrison Ford' has appeared - but not in the starring role. [Note: the ord field of casting gives the position of the actor. If ord=1 then this actor is in the starring role]*/

SELECT movie.title

FROM actor JOIN casting

ON (actor.id=casting.actorid)

JOIN movie

ON (movie.id = casting.movieid)

WHERE actor.name = 'Harrison Ford' AND casting.ord != 1;

--#10/*List the films together with the leading star for all 1962 films.*/

SELECT movie.title,actor.name

FROM actor JOIN casting

ON (actor.id=casting.actorid)

JOIN movie

ON (movie.id = casting.movieid)

WHERE movie.yr = 1962

AND casting.ord = 1;

知识点：MAX() 函数

MAX 函数返回一列中的最大值。NULL 值不包括在计算中。

MAX() 语法

SELECT MAX(column_name) FROM table_name

--#11

/*

Which were the busiest years for 'John Travolta', show the year and the number of movies he made each year for any year in which he made more than 2 movies.

*/

SELECT yr,COUNT(title) FROM

movie JOIN casting ON movie.id=movieid

JOIN actor ON actorid=actor.id

where name='John Travolta'

GROUP BY yr

HAVING COUNT(title)=(SELECT MAX(c) FROM

(SELECT yr,COUNT(title) AS c FROM

movie JOIN casting ON movie.id=movieid

JOIN actor ON actorid=actor.id

where name='John Travolta'

GROUP BY yr) AS t

)；

--#12

/*

List the film title and the leading actor for all of the films 'Julie Andrews' played in.

Did you get "Little Miss Marker twice"?

Julie Andrews starred in the 1980 remake of Little Miss Marker and not the original(1934).

Title is not a unique field, create a table of IDs in your subquery

*/

SELECT DISTINCT m.title,a.name

FROM (SELECT movie.*

FROM actor JOIN casting

ON (actor.id=casting.actorid)

JOIN movie

ON (movie.id = casting.movieid)

WHERE actor.name = 'Julie Andrews') AS m

JOIN (SELECT actor.*,casting.movieid AS movieid

FROM actor JOIN casting

ON (actor.id=casting.actorid)

WHERE casting.ord = 1) AS a

ON m.id = a.movieid

ORDER BY m.title;

--#13

/*

Obtain a list, in alphabetical order, of actors who've had at least 30 starring roles.

*/

SELECT actor.name

FROM actor

JOIN casting

on (actor.id = casting.actorid)

WHERE casting.ord = 1

GROUP BY actor.name

HAVING COUNT(*) >= 30;

--#14

/*

List the films released in the year 1978 ordered by the number of actors in the cast, then by title.

*/

SELECT movie.title, COUNT(actorid) AS cast_actors

FROM movie

JOIN casting

ON movie.id = casting.movieid

JOIN actor

ON actor.id = casting.actorid

WHERE movie.yr = 1978

GROUP BY movie.title

ORDER BY cast_actors DESC,movie.title;

--#15

/*

List all the people who have worked with 'Art Garfunkel'.

*/

SELECT a.name

FROM (SELECT movie.*

FROM movie

JOIN casting

ON casting.movieid = movie.id

JOIN actor

ON actor.id = casting.actorid

WHERE actor.name = 'Art Garfunkel') AS m

JOIN (SELECT actor.*, casting.movieid

FROM actor

JOIN casting

ON casting.actorid = actor.id

WHERE actor.name != 'Art Garfunkel') as a

ON m.id = a.movieid;