心心念念的安卓简单和多功能计算器来了

一、应用介绍

安卓计算器：
实现功能：
（1）能实现基本的加减乘除运算、回退和清空输入。
（2）竖屏时能实现基本的加减乘除运算、回退和清空输入。横屏时变为科学计算器，实现函数计算、进制换算等功能。
（3）数字按键依照电话拨号键盘顺序排列。
（4）点击菜单可对计算器相关特性进行配置。
（5）输入计算公式，按等号键输出计算结果。
（6）公式输入和结果显示区应支持长按弹出复制、粘贴功能。
（7）使用计算器过程中应不弹出软键盘。
（8）可以通过进度条实时调整计算结果保留的小数点后位数，或者通过音量键完成同样的效果。
（9）实现附加功能：三角函数、阶乘、XY、√(Y&X)及括号，如sin(90)。
（10）输入表达式按优先级计算，按等号输出结果。
（11）对常用键布局需考虑特殊处理。
（12）处理精度和容错问题：
a.1/3+1/3+1/3；
2.1+0.001；
1.1-1.001；
1/0、1/(1-1)和1/sin(0)等;
3/2;
对有附加功能的需要处理特殊值，如：√(2&-1) 等。

二、运行截图

竖屏时

横屏时

主要代码
MainActivity.java

public class MainActivity extends AppCompatActivity {String formula = "";//公式方程Boolean zeroMark = true; //允许输入一个0Boolean zeroCon = false;//允许持续输入0Boolean docMark = true;// . 可以输入 .Boolean resultMark = false; //结果是否计算出Boolean transformMark = false; //是否进行二进制转化Boolean errorMark = false;Boolean numAndOpMark = true;int color = 0xffffffff;private static final String REGEX = "^\\d+$";//all is numint precision = 3; //保留小数点位数@Overrideprotected void onCreate(Bundle savedInstanceState) {super.onCreate(savedInstanceState);setRequestedOrientation(ActivityInfo.SCREEN_ORIENTATION_FULL_SENSOR); //屏幕旋转setContentView(R.layout.col);EditText show = findViewById(R.id.show);show.setText("");show.setSelectAllOnFocus(true);  // 设置长按时选择全部calculator();}public void calculator() {disableShowInput(); // 不让弹出软键盘EditText show = findViewById(R.id.show);Button dot = findViewById(R.id.dot);Button zero = findViewById(R.id.zero);Button one = findViewById(R.id.one);Button two = findViewById(R.id.two);Button three = findViewById(R.id.three);Button four = findViewById(R.id.four);Button five = findViewById(R.id.five);Button six = findViewById(R.id.six);Button seven = findViewById(R.id.seven);Button eight = findViewById(R.id.eight);Button nine = findViewById(R.id.nine);Button add = findViewById(R.id.add);Button sub = findViewById(R.id.sub);Button division = findViewById(R.id.division);Button back = findViewById(R.id.back);Button AC = findViewById(R.id.AC);Button mul = findViewById(R.id.mul);Button eval = findViewById(R.id.eval);Button percent = findViewById(R.id.percent);Button sin = findViewById(R.id.sin);Button power = findViewById(R.id.power);Button factorial = findViewById(R.id.factorial); //阶乘Button square = findViewById(R.id.square); //开根号Button brackets = findViewById(R.id.brackets);Button transform = findViewById(R.id.transform);dot.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {doNum(".");}});zero.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {doNum("0");}});one.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {doNum("1");}});two.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {doNum("2");}});three.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {doNum("3");}});four.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {doNum("4");}});five.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {doNum("5");}});six.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {doNum("6");}});seven.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {doNum("7");}});eight.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {doNum("8");}});nine.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {doNum("9");}});add.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {doOp("+");}});sub.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {doOp("-");}});mul.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {doOp("×");}});division.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {doOp("÷");}});AC.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {reSetStatus();show.setText("");}});back.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {if (formula.length() > 0) {if (!formula.contains("(D->B)")) {if (lastStr().equals(".")) {docMark = true;}formula = formula.substring(0, formula.length() - 1);} else {formula = formula.replace("(D->B)", "");numAndOpMark = true;transformMark = false;}show.setText(formula);show.setTextColor(0xff000000);}}});eval.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {try {String result = "";if (transformMark) {  // 先判断是不是要进行二进制转化doTransform();return;}delLastOp(); // 如果式子是 4- 进行计算,我们打算将-号去掉,结果为4try {result = Result.getRes(formula) + ""; //将计算式放入getRes函数中进行计算} catch (Exception e) {show.setText(e.getMessage()); //getRes中抛出的异常进行抓取并显示show.setTextColor(0xffff0000);errorMark = true;return;}System.out.println(result + "result");if (result.contains("E") && !result.contains("E-")) {// 结果使用了科学计数法表示,我们要根据情况进行处理show.setText(result);Toast toast = Toast.makeText(getApplicationContext(), "数值太大,已用科学计数法表示", Toast.LENGTH_SHORT);toast.show();return;}
//                    String intPart;//              if (result.length() > 12) {if (result.contains("E-")) {BigDecimal decimal = new BigDecimal(result);result = decimal.toPlainString();}if (result.length() > 12){result = result.substring(0, 11);}result = doPrecision(result);  //进行精读修改show.setText(result);reSetStatus();formula = result;resultMark = true;docMark = true;} catch (Exception e) {e.printStackTrace();}}});percent.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {if (formula.length() > 0) {if (!numAndOpMark) {return;}formula = "(" + formula + ")*0.01";try {show.setText(doEval(formula));formula = doEval(formula);} catch (Exception e) {show.setText(e.getMessage());}}}});sin.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {if (!numAndOpMark) {return;}formula = formula + "sin(";show.setText(formula);}});square.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {if (!numAndOpMark) {return;}formula = formula + "v(";show.setText(formula);}});power.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {if (!numAndOpMark) {return;}formula = formula + "^";show.setText(formula);}});factorial.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {if (!numAndOpMark) {return;}try {if (formula.contains(".") ){Toast toast = Toast.makeText(getApplicationContext(), "小数不可以阶乘", Toast.LENGTH_SHORT);toast.show();return;}if (Result.getRes(formula) < 171) {formula = formula + "!";show.setText(formula);} else {Toast toast = Toast.makeText(getApplicationContext(), "数值太大!", Toast.LENGTH_SHORT);toast.show();show.setTextColor(0xffff0000);resultMark = true;}} catch (Exception e) {e.printStackTrace();}}});brackets.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {if (!numAndOpMark) {return;}if (lastIsNum() || lastStr().equals(")")) {formula = formula + ")";} else {formula = formula + "(";}show.setText(formula);}});transform.setOnClickListener(new View.OnClickListener() {@Overridepublic void onClick(View v) {if (formula.matches(REGEX)) {formula = formula + "(D->B)";show.setText(formula);transformMark = true;numAndOpMark = false;}}});}public String doPrecision(String result) {System.out.println(result + "rep");String tail = result.split("\\.")[1];String pre = result.split("\\.")[0];int deltaPre = precision - tail.length();if (deltaPre > 0) {for (int i = 0; i < deltaPre; i++) {result = result + "0";}} else if (deltaPre < 0) {double doubleResult = Double.parseDouble(result);BigDecimal bigResult = new BigDecimal(doubleResult);result = bigResult.setScale(precision, BigDecimal.ROUND_HALF_UP).toString();}System.out.println(result + "pre");return result;}public void reSetStatus() {  //将各个监控状态设为初始状态EditText show = findViewById(R.id.show);show.setTextColor(0xff000000);formula = "";zeroMark = true;zeroCon = false;docMark = true;resultMark = false;transformMark = false;numAndOpMark = true;}@SuppressLint("SetTextI18n")public void doTransform() {  //二进制转化方法EditText show = findViewById(R.id.show);transformMark = false;String num = formula.split("\\(")[0];show.setText(Integer.toBinaryString(Integer.parseInt(num)) + "B");resultMark = true;docMark = true;}public String lastStr() {if (formula.length() > 0) {return formula.charAt(formula.length() - 1) + "";} else {return "";}}  //返回字符的最后一个字符public String doEval(String formula) throws Exception {  //做简单的计算方法ScriptEngineManager manager = new ScriptEngineManager();ScriptEngine se = manager.getEngineByName("js");return se.eval(formula) + "";}public Boolean lastIsNum() {  //最后一位是不是数字if (formula.length() == 0) {return false;} else {char lastChar = formula.charAt(formula.length() - 1);return lastChar > 47 && lastChar < 58;}}public Boolean lastIsOp() {  //最后一位字符是不是操作符return isOp(lastStr());}public Boolean isOp(String str) {  //传递的参数是不是操作符return (str.equals("+") || str.equals("×")|| str.equals("÷") || str.equals("-"));}public void doNum(String num) {EditText show = findViewById(R.id.show);show.setTextColor(0xff000000);int length = formula.length();if (!numAndOpMark) {  //当使用(D->B)后我们不再允许进行任何符号的输入return;}if (errorMark) {  //是否出错reSetStatus();errorMark = false;}if (resultMark) { //结果是否已算出formula = "";resultMark = false;}if (num.equals(".")) {  //输的字符是不是点   .000000000000if (docMark) { // && !isOp(lastStr())formula = formula + '.';show.setText(formula);docMark = false;zeroCon = true;}return;}if (num.equals("0")) {  //是不是0?   00000000000if (zeroCon || zeroMark) {formula = formula + '0';}show.setText(formula);zeroMark = false;return;}if (formula.startsWith("0") && length == 1) {  //0的特殊情况   09 -> 9formula = "";}if (length > 2 && formula.endsWith("0") && isOp(formula.charAt(length - 2) + "")) {formula = formula.substring(0, length - 1); // 0的特殊情况  23 + 09  -> 23 + 9}formula = formula + num;  //加入计算式zeroCon = true;show.setText(formula);}public void doOp(String op) {EditText show = findViewById(R.id.show);show.setTextColor(0xff000000);if (!numAndOpMark || lastStr().equals(".")) {return;}if (errorMark) {  //是否有错误  - is okreSetStatus();errorMark = false;}if (resultMark) { //结果是否计算出formula = show.getText().toString();resultMark = false;}if ((lastStr().equals("÷") || lastStr().equals("×")) && op.equals("-")) {addOp(op);return;}if (formula.contains("×-") || formula.contains("÷-")) {formula = formula.substring(0, formula.length() - 2);}if (formula.length() == 1 && lastStr().equals("-")) {  // 只有一个减号,不允许输任何操作符return;}if (formula.length() == 0 || lastStr().equals("(")) {  //1+(?=-if (op.equals("-")) { // 第一个输入的字符是不是-addOp(op);}return;}if (lastIsOp() && formula.length() > 0) {  //若最后一个字符已经时操作符,那要替换掉旧的替换符formula = formula.substring(0, formula.length() - 1);}addOp(op);  //如果没有以上特殊情况,则加到计算式里}public void addOp(String op) { // 输入操作符时大部分的重复工作进行封装EditText show = findViewById(R.id.show);formula = formula + op;docMark = true;zeroMark = true;zeroCon = false;show.setText(formula);}//==================================================================================@SuppressLint("SetTextI18n")@Overridepublic boolean onKeyDown(int keyCode, KeyEvent event) {  //设置精度(通过音量键)TextView info = findViewById(R.id.info);switch (keyCode) {case KeyEvent.KEYCODE_VOLUME_DOWN:if (precision > 1) {precision--;info.setText("保留" + precision + "位");Toast.makeText(this, "保留" + precision + "位", Toast.LENGTH_SHORT).show();} else {Toast.makeText(this, "至少保留1位", Toast.LENGTH_SHORT).show();}break;case KeyEvent.KEYCODE_VOLUME_UP:if (precision < 10) {precision++;Toast.makeText(this, "保留" + precision + "位", Toast.LENGTH_SHORT).show();info.setText("保留" + precision + "位");} else {Toast.makeText(this, "至多保留10位", Toast.LENGTH_SHORT).show();}break;}return super.onKeyDown(keyCode, event);}@SuppressLint("SetTextI18n")@Overridepublic void onConfigurationChanged(Configuration newConfig) {  //横竖屏切换时进行设置@SuppressLint("CutPasteId") EditText show1 = findViewById(R.id.show);color = show1.getCurrentTextColor();formula = show1.getText().toString(); //如果你是复制进去的式子,那必须先从show中得到式子// TODO Auto-generated method stubsuper.onConfigurationChanged(newConfig);//启动时默认是竖屏if (getResources().getConfiguration().orientation == Configuration.ORIENTATION_PORTRAIT) {setContentView(R.layout.col);@SuppressLint("CutPasteId") EditText show = findViewById(R.id.show);show.setText(formula);show.setTextColor(color);calculator();}//切换就是横屏else if (getResources().getConfiguration().orientation == Configuration.ORIENTATION_LANDSCAPE) {setContentView(R.layout.row);@SuppressLint("CutPasteId") EditText show = findViewById(R.id.show);TextView info = findViewById(R.id.info);info.setText("保留" + precision + "位");show.setText(formula);show.setTextColor(color);calculator();}}//========================================================================================@Overridepublic boolean onCreateOptionsMenu(Menu menu) {  //生成菜单项MenuInflater inflater = new MenuInflater(this);inflater.inflate(R.menu.menu, menu);return super.onCreateOptionsMenu(menu);}@SuppressLint("NonConstantResourceId")@Override  //菜单项无所谓public boolean onOptionsItemSelected(MenuItem item) {EditText show = findViewById(R.id.show);//先判断点击的是哪个idswitch (item.getItemId()) {case R.id.font_10:show.setTextSize(10 * 2);break;case R.id.font_12:show.setTextSize(12 * 2);break;case R.id.font_14:show.setTextSize(14 * 2);break;case R.id.font_16:show.setTextSize(16 * 2);break;case R.id.font_18:show.setTextSize(18 * 2);break;case R.id.blue:show.setTextColor(Color.BLUE);break;case R.id.red:show.setTextColor(Color.RED);break;case R.id.green:show.setTextColor(Color.GREEN);break;}return super.onOptionsItemSelected(item);}//======================================================================================public void disableShowInput() {  //设置键盘不可见EditText show = findViewById(R.id.show);Class<EditText> cls = EditText.class;Method method;try {method = cls.getMethod("setShowSoftInputOnFocus", boolean.class);method.setAccessible(true);method.invoke(show, false);} catch (Exception e) {//TODO: handle exception}try {method = cls.getMethod("setSoftInputShownOnFocus", boolean.class);method.setAccessible(true);method.invoke(show, false);} catch (Exception e) {//TODO: handle exception}}//=============================================================================public void delLastOp() {  //写个小递归,后来想想好像用不到,但懒得改了if (isOp(formula.charAt(formula.length() - 1) + "") || lastStr().equals(".")) {formula = formula.substring(0, formula.length() - 1);delLastOp();}}

ArrayStack.java


class ArrayStack {private int maxSize; // 栈的大小private double[] stack; // 数组，数组模拟栈，数据就放在该数组private int top = -1;// top表示栈顶，初始化为-1//构造器public ArrayStack(int maxSize) {this.maxSize = maxSize;stack = new double[this.maxSize];}//增加一个方法，可以返回当前栈顶的值, 但是不是真正的poppublic double peek() {return stack[top];}//栈满public boolean isFull() {return top == maxSize - 1;}//栈空public boolean isEmpty() {return top == -1;}//入栈-pushpublic void push(double value) {//先判断栈是否满if (isFull()) {System.out.println("表达式错误");return;}top++;stack[top] = value;}//出栈-pop, 将栈顶的数据返回public double pop() {//先判断栈是否空if (isEmpty()) {//抛出异常throw new RuntimeException("表达式错误");}double value = stack[top];top--;return value;}//显示栈的情况[遍历栈]， 遍历时，需要从栈顶开始显示数据public void list() {if (isEmpty()) {System.out.println("表达式错误");return;}//需要从栈顶开始显示数据for (int i = top; i >= 0; i--) {System.out.printf("stack[%d]=%d\n", i, stack[i]);}}//返回运算符的优先级，优先级是程序员来确定, 优先级使用数字表示//数字越大，则优先级就越高.public int priority(int oper) {if (oper == '*' || oper == '/') {return 1;} else if (oper == '+' || oper == '-') {return 0;} else if (oper == '^'||oper == '#') {return 2;} else if (oper == '!' || oper == 'v' || oper == '%') {return 3;} else if (oper == 's' || oper == 't' || oper == 'c') {return 4;} else {return -1; // 假定目前的表达式只有 +, - , * , /}}//判断是不是一个运算符public boolean isNum(char val) {return '0' <= val && val <= '9';}//判断是不是一个运算符public boolean isOper(char val) {return val == '+' || val == '-' || val == '*' || val == '/' || val == '#' || val == '^' || val == '%' || val == 's' || val == 'c' || val == 't' || val == '!' || val == 'v';}//判断是不是 (public boolean isLeftBrackets(char val) {return val == '(';}//判断是不是 )public boolean isRightBrackets(char val) {return val == ')';}//判断是不是 .public boolean isPoint(char val) {return val == '.';}//判断是不是 (public boolean isTrigonometric(char val) {return val == 's';}//计算方法public double cal(double num1, double num2, int oper) {double res = 0; // res 用于存放计算的结果switch (oper) {case '+':res = num1 + num2;break;case '-':res = sub(num2,num1);// 注意顺序break;case '*':res = num1 * num2;break;case '/':if (num1 == 0) {throw new RuntimeException("定义域错误");}res = num2 / num1;break;case '^':res = Math.pow(num2, num1);break;default:break;}return res;}/*** 三角函数运算、阶乘运算或者是开根操作** @param num1* @param oper* @return*/public double mixedOperation(double num1, int oper) {double res = 1; // res 用于存放计算的结果switch (oper) {case 's':res = Math.sin(num1 * Math.PI / 180);break;case 'c':res = Math.cos(num1 * Math.PI / 180);break;case 't':res = Math.tan(num1 * Math.PI / 180);break;case '!':for (int i = 1; i <= num1; i++) {res *= i;}break;case 'v':if (num1 < 0) {throw new RuntimeException("定义域错误");}res = Math.sqrt(num1);break;case '%':res = num1 / 100;break;case '#':res = -num1;break;default:break;}return res;}double sub(double x, double y) {BigDecimal initResult = new BigDecimal(x - y);   //计算初步结果String temp = initResult.toString();if (temp.contains(".")){temp = temp + "00000000000000000000";}else {temp = temp + ".00000000000000000000";}int lengthOfInt = getLengthOfInt(x, y);   //结果整形位数int lengthOfDec = Math.max(getLengthOfDecimal(x), getLengthOfDecimal(y));int count = lengthOfInt + lengthOfDec + 2;  //最后输出的位数 = 整形位数+小数位数+小数点位数+1(四舍五入舍去)double tempResult = Double.parseDouble(temp.substring(0, count)); //将String转换成double,并截取多一位用于四舍五入double power = Math.pow(10, lengthOfDec);  //求10的几次方用来四舍五入double finalResult = (double) (Math.round(tempResult * power)) / power;  //四舍五入Log.i("result", x + "-" + y + "=" + finalResult);//此处的长度取决于小数点后面位数大的return finalResult;}int getLengthOfInt(double x, double y) {int lengthOfInt;int intX = (int) x;  //x的整数部分int intY = (int) y;  //y的整数部分lengthOfInt = String.valueOf(intX - intY).length();   //结果整形部分的位数 = 相减后整形的位数return lengthOfInt;}int getLengthOfDecimal(double x) {return String.valueOf(x).split("\\.")[1].length(); //计算x小数点后面的位数}

public class Result {public static double getRes(String expression) {System.out.println(expression.length());expression = expression.replace("sin", "s");expression = expression.replace("÷", "/");expression = expression.replace("×", "*");ArrayStack stack=new ArrayStack(20);String exp = "";int count = 0;char[] chars = expression.toCharArray();while (count < chars.length) {if (count == 0 && chars[count] == '-') {chars[count] = '#';}if (count >= 1 && chars[count] == '-' && chars[count - 1] == '(') {chars[count] = '#';}if (count >= 1 && chars[count] == '-' && stack.priority(chars[count-1])>stack.priority(chars[count])) {chars[count] = '#';}exp += chars[count];count++;}expression=exp;//创建两个栈，数栈，一个符号栈ArrayStack numStack = new ArrayStack(20);ArrayStack operatorStack = new ArrayStack(20);//定义需要的相关变量int index = 0;//用于扫描double num1 = 0;double num2 = 0;int oper = 0;double res = 0;char ch = ' '; //将每次扫描得到char保存到chString keepNum = ""; //用于拼接 多位数//开始while循环的扫描expressionwhile (true) {//依次得到expression 的每一个字符ch = expression.substring(index, index + 1).charAt(0);//判断ch是什么，然后做相应的处理if (operatorStack.isLeftBrackets(ch)) {   //如果是左括号//直接入符号栈..operatorStack.push(ch);} else if (operatorStack.isRightBrackets(ch)) {  //如果是右括号while (operatorStack.peek() != '(') {  //循环直到能够到达 '(' 处oper = (int) operatorStack.pop();if (oper == 's' ||oper == '!' ||oper == 'v' ||oper == '#' ||oper == '%') {  //如果栈顶为三角函数、阶乘或者是开根num1 = numStack.pop();res = numStack.mixedOperation(num1, oper);//把运算的结果如数栈numStack.push(res);} else {num1 = numStack.pop();num2 = numStack.pop();res = operatorStack.cal(num1, num2, oper);//把运算的结果如数栈numStack.push(res);}}//然后将当前栈顶的操作符出符号栈----其实也就是 '(' 出栈operatorStack.pop();} else if (operatorStack.isOper(ch)) {   //如果是运算符if (operatorStack.isEmpty() || operatorStack.peek() == '(') {//如果符号栈为空，或者栈顶为'('operatorStack.push(ch);} else if (operatorStack.priority(ch) > operatorStack.priority((int) operatorStack.peek())) {//如果当前优先级比栈顶优先级高，直接入符号栈.operatorStack.push(ch);} else {while (!operatorStack.isEmpty() &&(operatorStack.priority(ch) <= operatorStack.priority((int) operatorStack.peek()))) {oper = (int) operatorStack.pop();if (!operatorStack.isEmpty() && (operatorStack.peek() == '!' ||operatorStack.peek() == 's' ||operatorStack.peek() == 'v' ||operatorStack.peek() == '#' ||operatorStack.peek() == '%')) {num1 = numStack.pop();res = numStack.mixedOperation(num1, oper);numStack.push(res);//入栈} else {if (oper == 's' ||oper == '!' ||oper == 'v' ||oper == '#' ||oper == '%') {  //如果栈顶为三角函数、阶乘或者是开根num1 = numStack.pop();res = numStack.mixedOperation(num1, oper);//把运算的结果如数栈numStack.push(res);} else {num1 = numStack.pop();num2 = numStack.pop();res = numStack.cal(num1, num2, oper);//把运算的结果如数栈numStack.push(res);}}}//然后将当前的操作符入符号栈operatorStack.push(ch);}} else if (operatorStack.isPoint(ch) || operatorStack.isNum(ch)) {   //如果是数或者是小数点，则直接入数栈//numStack.push(ch - 48); // "1+3" '1' => 1//1. 当处理多位数时，不能发现是一个数就立即入栈，因为可能是多位数//2. 在处理数，需要向expression的表达式的index 后再看一位,如果是数就进行扫描，如果是符号才入栈//3. 因此我们需要定义一个变量 字符串，用于拼接//处理多位数keepNum += ch;//如果ch已经是expression的最后一位，就直接入栈if (index == expression.length() - 1) {numStack.push(Double.parseDouble(keepNum));} else {//判断下一个字符是不是数字，如果是数字，就继续扫描，如果是运算符，则入栈//注意是看后一位，不是index++if (operatorStack.isOper(expression.substring(index + 1, index + 2).charAt(0))|| operatorStack.isRightBrackets(expression.substring(index + 1, index + 2).charAt(0))) {//如果后一位是运算符，则入栈 keepNum = "1" 或者 "123"numStack.push(Double.parseDouble(keepNum));//最后keepNum必须清空keepNum = "";}}} else if (!operatorStack.isEmpty() && (operatorStack.peek() == 's' ||operatorStack.peek() == '!' ||operatorStack.peek() == 'v' ||operatorStack.peek() == '#' ||operatorStack.peek() == '%')) {   //如果栈顶为三角函数算式、开根或者是阶乘oper = (int) operatorStack.pop();num1 = numStack.pop();res = numStack.mixedOperation(num1, oper);//把运算的结果入数栈numStack.push(res);}//让index + 1, 并判断是否扫描到expression最后.index++;if (index >= expression.length()) {break;}}//当表达式扫描完毕，就顺序的从 数栈和符号栈中pop出相应的数和符号，并运行.while (true) {//如果符号栈为空，则计算到最后的结果, 数栈中只有一个数字【结果】if (operatorStack.isEmpty()) {break;}if (operatorStack.peek() == 's' ||operatorStack.peek() == '!' ||operatorStack.peek() == 'v' ||operatorStack.peek() == '#' ||operatorStack.peek() == '%') {    //如果栈顶为三角函数算式oper = (int) operatorStack.pop();num1 = numStack.pop();res = numStack.mixedOperation(num1, oper);numStack.push(res);//入栈} else {num1 = numStack.pop();num2 = numStack.pop();oper = (int) operatorStack.pop();res = numStack.cal(num1, num2, oper);numStack.push(res);//入栈}}//将数栈的最后数，pop出，就是结果double res2 = numStack.pop();System.out.println(res2+"ll");return res2;}

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心心念念的安卓简单和多功能计算器来了

一、应用介绍

二、运行截图

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心心念念的安卓简单和多功能计算器来了

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二、运行截图