Codeforces 839B - Game of the Rows

839B - Game of the Rows

思路：先放4个的，然后再放2个的，最后再放1个的。

代码：

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define pb push_back
#define mem(a,b) memset((a),(b),sizeof(a))
int a[105];int main()
{int n,k;cin>>n>>k;int c2=n*2; int c4=n;for(int i=1;i<=k;i++)cin>>a[i];for(int i=1;i<=k;i++){int c=min(c4,a[i]/4);c4-=c;a[i]-=c*4;}c2+=c4;//剩下的4个连在一起的也可以放2个的 for(int i=1;i<=k;i++){int c=min(c2,a[i]/2);c2-=c;a[i]-=c*2;}int t=c2+c4;//原来的4个连在一起的放二个的时候只放了一半，而且放了一半也可能没放满 for(int i=1;i<=k;i++){t-=a[i];}if(t<0)cout<<"NO"<<endl;else cout<<"YES"<<endl;return 0;
}

转载于:https://www.cnblogs.com/widsom/p/7353437.html

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