字符串 -- 3.15 Length of Last Word -- 图解

描述
Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the
length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example, Given s = "Hello World", return 5.

class Solution{
public:int lengthOfLastWord(const char *s){const string str(s);auto first = first_if(str.rbegin(), str.rend(); ::isalpha);auto last = first_if_not(first , str.rend(), ::isalpha);return distance(first, last);}
};class Solution{
public:int LengthofLastWorld(string str){int res = 0;int length = str.size();int i = 0;int lastspaceindex = 0;while (i<length){if (str[i] == ' ')lastspaceindex = i;i++;}return length - lastspaceindex - 1;}
};

参考资料：

LeetCode题解

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