Jay Chan 用 C 语言写的一个迷你版 2048 游戏，仅仅有 487 个字符。

来围观吧

M[16],X=16,W,k;main(){T(system("stty cbreak")
);puts(W&1?

"WIN":"LOSE");}K[]={2,3,1};s(f,d,i ,j,l,P){for(i=4;i--;)for(j=k=l=0;k<4;)j<4?

P=M [w(d,i,j++)],W|=P>>11,l*P&&(f?M[w(d,i,k)]=l<< (l==P):0,k++),l=l?P?l-P?P:0:l:P:(f?M[w(d,i,k) ]=l:0,++k,W|=2*!l,l=0);}w(d,i,j){return d?w(d -1,j,3-i):4*i+j;}T(i){for(i=X+rand()%X;M[i%X] *i;i--);i?

M[i%X]=2<<rand()%2:0;for(W=i=0;i<4; )s(0,i++);for(i=X,puts("\e[2J\e[H");i--;i%4|| puts(""))printf(M[i]?"%4d|":" |",M[i]);W-2 ||read(0,&k,3)|T(s (1,K[(k>>X)%4]));}

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <time.h>#define GRID_LEN 16int M[GRID_LEN];
int X = GRID_LEN;
int W;
int k;
int K[] = { 2, 3, 1 };int w (int d, int i, int j)
{if (d <= 0) {return 4 * i + j;}return w (d - 1, j, 3 - i);
}void s (int f, int d)
{int i = 4, j, l, P;for (; i--;) {j = k = l = 0;for (; k < 4;) {if (j < 4) {P = M[w (d, i, j++)];W |= P >> 11;l *P && (f ? M[w (d, i, k)] = l << (l == P) : 0, k++);l = l ? (P ? (l - P ?

P : 0) : l) : P; } else { f ? M[w (d, i, k)] = l : 0; ++k; W |= 2 * !l; l = 0; } } } } void T () { int i = X + rand () % X; for (; M[i % X] * i; i--); i ? M[i % X] = 2 << rand () % 2 : 0; W = i = 0; for (; i < 4; i++) { s (0, i); } // Prints the tiles onto the terminal i = X; puts ("\e[2J\e[H"); for (; i--;) { if (M[i]) { printf ("%4d|", M[i]); } else { printf ("%s", " |"); } // every 4th cell is followed by a line-break if (0 == (i & 3)) { putchar ('\n'); } } // read input from keyboard if (!(W - 2)) { read (0, &k, 3); s (1, K[(k >> X) % 4]); T (); } } int main (void) { // Uses stty to clear the screen in preparation for the game //system ("stty cbreak"); /* Intializes random number generator */ srand ((unsigned) time (NULL)); T (); // Game has finished by this point // If win, display "WIN". Otherwise, display "LOSE". puts (W & 1 ? "WIN" : "LOSE"); return 0; }