def func():print("哈哈")yield 1
gen = func()  #不会执行函数,拿到的是生成器

def order():for i in range(10000):yield "衣服"+str(i)
g = order() # 获取生成器
mingwei = g.__next__()
print(mingwei)
zhaoyining = g.__next__()
print(zhaoyining)

def eat():print("我吃什么啊")a =  yield  "馒头"print("a=",a)b =  yield  "鸡蛋灌饼"print("b=",b)c =  yield  "韭菜盒子"print("c=",c)yield  "GAME OVER"
gen = eat()      # 获取生成器

ret1 = gen. __next__()
print(ret1) # 馒头
ret2 = gen.send("胡辣汤")
print(ret2)ret3 = gen.send("狗粮")
print(ret3)
ret4 = gen.send( "猫粮")
print(ret4)

for i in func(): # for的内部一定有__next__()print(i)print(list(func())) # 内部都有__next__()

lst = []
for i in range(1, 16):lst.append("python"+str(i))
print(lst)

lst = ["python"+str(j) for j in range(1,16)]
print(lst)

lst = ["pytjon"+str(j) for j in range(1,6)]
print(lst)

View Code

lst = [i for i in range(1000) if i%2==1]
print(lst)

奇数

lst = [i*i for i in range(100) if i%3==0]
print(lst)

100以内能被3整除的数的平方

#寻找名字中带两个e的人的名字
name = [["Tom","Billy","Jefferson","Andrew","Wesley","Steven","Joe"],
["Alice","Jill","Ana","Wendy","Jennifer","Sherry"]]
lst = [name for line in names for name in line if type(name)==str and name.count("e")==2]
print(lst)

#[11,22,33,44]  =>{0:11, 1:22, 2:33, 3:44}
lst = [11,22,33,44]
dic = {i:lst[i]  for i in range(len(lst)) if i < 2}
print(dic)dic = {"jj": "林俊杰", "jay": "周杰伦", "zs": "赵四", "ln":"刘能"}
d = {v : k for k,v in dic.items()}
print(d)

s = {i for i in range(100)} # 可去除重复
print(s)

#生成器函数
def func():print(111)yield 222yield 333
g = func #获取生成器
g1 = (i for i in g)#生成器
g2 = (i for i in g1) #生成器
print(list(g))  #[222,333] 源头,从源头把数据拿走了
print(list(g1))  #[]    这里执行的时候,源头已经没有数据了
print(list(g2))  #[]   这里也没有值了

# 求和
def add(a, b):return a  + b# 生成器函数 #  0-3
def test():for r_i in range(4):yield  r_i# 0,1,2,3
g = test() # 获取生成器for n in  [2, 10]:g = (add(n, i) for i in g)
print(g)# 到最后往里面放数据就对了
# print(list(g))
# print(list(g)) # []