27/100. Intersection of Two Linked Lists
查找两个单独链表开始相交的节点。
p1从链表A的头节点开始走，p2从链表B的头节点开始走，当它们走到当前链表的尾节点时，从另一链表的头节点开始走（p1走链表B，p2走链表A）。
这样其实当它们走到相交的节点时，正好走过的路径长度是一样的。
# Definition for singly-linked list.
# class ListNode(object):
# def __init__(self, x):
# self.val = x
# self.next = Noneclass Solution(object):def getIntersectionNode(self, headA, headB):""":type head1, head1: ListNode:rtype: ListNode"""if not headA or not headB:return Nonep1 = headAp2 = headBwhile p1 != p2:p1 = p1.next if p1 else headBp2 = p2.next if p2 else headAreturn p1
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