1.格式化字符串--------------------------------------name = input("your name:")age = input("your age:")if age.isdigit():    age = int(age)else:   # print("plz input a num")    exit("plz input a num")job= input("your job:")

info ='''-------------the info of %s -----------     the name is %s    the age is %d    the job is %s    -------------------    ''' % (name,name,age,job) #这里的百分号和里面的值，对应上面的占位符 %s表字符串 %d 表数字 %f 表浮点数

print(info)

2---------------for----------------

# for i in range(1,100,2):# 1,表示起始 100，表示最终，2 表示步长。 （不写默认为1步）。#     print(i)

_name = "ming"_password = "abc"

for i in range(1,4):    name = input("input you name:")    password = input("input you password:")    if _name == name and _password == password:        print("well come %s to our club" % name )        break    else:        print("there is no more than %s times" % (3-i) )        if  i == 3:            exit(" you have on chance")

3--------------break-----------------------break_flag = Falsefor i in range(10):    print(i)    if i==9:        for j in range(10):            print("lak2",j)            if j==5:                break_flag=True                break    if break_flag==True:        break

4-------------list count-------------------------

a=['br','td','td','tr','br'].count('br') #统计tr出现的个数b=['br','td','td','tr','br']c=['3',3]c.extend(b) #把C扩展b里的内容print(a)print(b)print(c)

#index 查找内容所在的位置d=c.index('td') # 即查td所在的位置print(d)

#reverse 倒序print(c,'@@@@@@@正序')k = c.reverse() #这个没有返回值，print(k,'#---c.reverse() 这个没有返回值 -----倒序#')print(c,'--------倒序')#当然还可以这样子e = c[::-1] #这个就有返回值了print(e,'####，再倒序')