java math 类

数学课静态长回合(双D) (Math Class static long round(double d) )

• This method is available in java.lang package.

  此方法在java.lang包中可用。

• This method is used to return the closest long value to the given argument.

  此方法用于将最接近的long值返回给定参数。

• This is a static method, it is accessible with the class name too.

  这是一个静态方法，也可以使用类名进行访问。

• The return type of this method is long, it returns the long type number which will be converted from double floating to long by adding 1/2 of the given argument.

  此方法的返回类型为long ，它返回long类型号，通过添加给定参数的1/2可以将其从double浮点数转换为long类型。

• In this method, we pass only one parameter of a double type value.

  在此方法中，我们仅传递一个double类型值的参数。

• If the value of the given argument after the decimal point is greater than 4 then the value is incremented by 1 before the decimal point is returned else if the value of the given argument after the decimal point is less than or equal to 4 then the same value before the decimal point is returned.

  如果小数点后给定参数的值大于4，则在返回小数点前将值加1；否则，如果小数点后给定参数的值小于或等于4，则相同返回小数点前的值。

• This method does not throw any exception.

  此方法不会引发任何异常。

Syntax:

句法：

    public static long round(double d){
}

Parameter(s): d – a double value whose closest to long value to be found.

参数： d –一个双精度值，其最接近要找到的long值。

Note:

注意：

• If we pass "NaN" (Not a Number), it returns 0.

  如果传递“ NaN”(非数字)，则返回0。

• If we pass negative infinity, it returns the "Long.MIN_VALUE".

  如果我们传递负无穷大，它将返回“ Long.MIN_VALUE”。

• If we pass positive infinity, it returns the "Long.MAX_VALUE".

  如果我们传递正无穷大，它将返回“ Long.MAX_VALUE”。

• If we pass the value which is less than or equal to "Long.MIN_VALUE", it returns "Long.MIN_VALUE".

  如果传递的值小于或等于“ Long.MIN_VALUE”，则返回“ Long.MIN_VALUE”。

• If we pass the value which is greater than or equal to "Long.MAX_VALUE", it returns "Long.MAX_VALUE".

  如果传递的值大于或等于“ Long.MAX_VALUE”，则返回“ Long.MAX_VALUE”。

Return value:

返回值：

The return type of this method is long, it returns a long value which is the closest to long value of given parameter.

此方法的返回类型为long ，它返回一个long值，该值最接近给定参数的long值。

Java程序演示round(double d)方法的示例 (Java program to demonstrate example of round(double d) method)

// Java program to demonstrate the example of
// round(double d) method of Math Class.
public class RoundMethod {public static void main(String[] args) {// declaring the variables
double d1 = -1.0 / 0.0;
double d2 = 1.0 / 0.0;
double d3 = 1234.56;
double d4 = 1234.42;
// Here , we will get (Long.MIN_VALUE) and we are
// passing parameter whose value is (-Infinity)
System.out.println("Math.round(d1): " + Math.round(d1));
// Here , we will get (Long.MAX_VALUE) and we are
// passing parameter whose value is (Infinity)
System.out.println("Math.round(d2): " + Math.round(d2));
// Here , we will get (1235) and we are
// passing parameter whose value is (1234.56)
System.out.println("Math.round(d3): " + Math.round(d3));
// Here , we will get (1234) and we are
// passing parameter whose value is (1234.12)
System.out.println("Math.round(d4): " + Math.round(d4));
}
}

Output

输出量

E:\Programs>javac RoundMethod.java
E:\Programs>java RoundMethod
Math.round(d1): -9223372036854775808
Math.round(d2): 9223372036854775807
Math.round(d3): 1235
Math.round(d4): 1234

翻译自: https://www.includehelp.com/java/math-class-static-long-round-double-d-with-example.aspx

java math 类