29/100. Counting Bits

给定一个非负整数num。对于0≤i≤num范围内的每个数字i，计算其二进制表示形式中的1的个数，并将其作为数组返回。

class Solution(object):def countBits(self, num):""":type num: int:rtype: List[int]"""r = [0]  # bin(0)=0a = 1  #2的0次方for i in range(1, num+1):r.append(r[i-a]+1)if i == 2*a-1:a = 2*a  # 2的n次方return r

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