##1. 两种java实现zip文件解压方式

• 使用JDK的原生类java.util.zip，上代码：

import java.util.zip.*;
import java.io.*;public class UnzipTest {public static void main(String[] args) {if (args.length != 1) {System.out.println("请输入正确参数：java UnzipTest 需解压的文件(e.g. d:/test.zip)");} else {Unzip unzip = new Unzip();if (unzip.unzip(args[0])) {System.out.println("文件解压成功。");} else {System.out.println("文件解压失败。");}}    }
}class Unzip {public Unzip() {}/** @param srcZipFile 需解压的文件名* @return  如果解压成功返回true*/public boolean unzip(String srcZipFile) {boolean isSuccessful = true;try {BufferedInputStream bis = new BufferedInputStream(new FileInputStream(srcZipFile));ZipInputStream zis = new ZipInputStream(bis);BufferedOutputStream bos = null;//byte[] b = new byte[1024];ZipEntry entry = null;while ((entry=zis.getNextEntry()) != null) {String entryName = entry.getName();bos = new BufferedOutputStream(new FileOutputStream("d:/" + entryName));int b = 0;while ((b = zis.read()) != -1) {bos.write(b);}bos.flush();bos.close();}zis.close();} catch (IOException e) {isSuccessful = false;}return isSuccessful;}
}

这种解压方式会出现中文文件名乱码的问题。

• 另一种实现zip文件解压的方式，使用 ant.jar 的org.apache.tools.zip包，上代码：

import java.io.*;
import java.util.Enumeration;
import org.apache.tools.ant.Project;
import org.apache.tools.ant.taskdefs.Expand;
import org.apache.tools.zip.ZipEntry;
import org.apache.tools.zip.ZipFile;
import org.mockito.internal.util.io.IOUtil;public class Unzip {private static final String ENCODE = "UTF-8";/** @param zipDir目标文件存放地，zipFile带解压文件* @return  如果解压成功返回true*/public static boolean unzip(String zipDir, String zipFile) {ZipFile zfile = null;InputStream is = null;OutputStream os = null;try{zfile = new ZipFile(zipFile);Enumeration<?> zList = zfile.getEntries();ZipEntry ze = null;byte[] buf = new byte[1024];while (zList.hasMoreElements()){ze = (ZipEntry) zList.nextElement();if (ze.isDirectory()){/*// 获得当前时间DateFormat format = new SimpleDateFormat("yyyyMMddHHmmss");// 转换为字符串String formatDate = format.format(new Date());// 随机生成文件编号int random = new Random().nextInt(10000);*/File f = new File(zipDir + ze.getName());f.mkdir();continue;}os = new BufferedOutputStream(new FileOutputStream(getRealFileName(zipDir, ze.getName())));is = new BufferedInputStream(zfile.getInputStream(ze));int readLen = 0;while ((readLen = is.read(buf, 0, 1024)) != -1){os.write(buf, 0, readLen);}IOUtil.closeQuietly(is);IOUtil.closeQuietly(os);}zfile.close();return true;}catch (IOException e){e.printStackTrace();}finally{IOUtil.closeQuietly(is);IOUtil.closeQuietly(os);try{if (null != zfile){zfile.close();}}catch (IOException ex){// ignoreSystem.out.println(ex);}}return false;}/*** 给定根目录，返回一个相对路径所对应的实际文件名.** @param baseDir*            指定根目录* @param absFileName*            相对路径名，来自于ZipEntry中的name* @return java.io.File 实际的文件*/public static File getRealFileName(String baseDir, String absFileName){String[] dirs = absFileName.split("/");File ret = new File(baseDir);if (dirs.length > 1){for (int i = 0; i < dirs.length - 1; i++){ret = new File(ret, dirs[i]);}if (!ret.exists())ret.mkdirs();ret = new File(ret, dirs[dirs.length - 1]);return ret;}ret = new File(ret, dirs[dirs.length - 1]);return ret;}
}

ant.jar的maven依赖

<dependency><groupId>org.apache.ant</groupId><artifactId>ant</artifactId><version>1.10.1</version>
</dependency>

第二种方法可以避免中文文件名乱码的问题。