我对运行代码后在命令窗口中得到的输出有点困惑。我对每一部分都复习了几遍，我不知道哪里出了问题。在

为什么字典计数打印，但其余打印语句没有显示？我还检查了SQLite文件中的表，表中没有我的数据，只有标题。在

我忽略了什么吗？不会出现错误，但它不会给出表中的输出或数据，即使使用insert、select和fetchone语句也是如此。在

提前感谢您的评论！在

以下是我一直在玩的东西：import xml.etree.ElementTree as ET

import sqlite3

conn = sqlite3.connect('trackdb.sqlite')

cur = conn.cursor()

cur.excutescript('''

DROP TABLE IF EXISTS Artist;

DROP TABLE IF EXISTS Album;

DROP TABLE IF EXISTS Track;

DROP TABLE IF EXISTS Genre;

CREATE TABLE Artist (

id INTEGER NOT NULL PRIMARY KEY AUTOINCREMENT UNIQUE,

name TEXT UNIQUE

);

CREATE TABLE Genre (

id INTEGER NOT NULL PRIMARY KEY AUTOINCREMENT UNIQUE,

name TEXT UNIQUE

);

CREATE TABLE Album (

id INTEGER NOT NULL PRIMARY KEY AUTOINCREMENT UNIQUE,

artist_id INTEGER,

title TEXT UNIQUE

);

CREATE TABLE Track (

id INTEGER NOT NULL PRIMARY KEY

AUTOINCREMENT UNIQUE,

title TEXT UNIQUE,

album_id INTEGER,

genre_id INTEGER,

len INTEGER, rating INTEGER, count INTEGER

);

''')

fname = raw_input('Enter file name: ')

if ( len(fname) < 1 ) : fname = 'Library.xml'

# Track ID369

# NameAnother One Bites The Dust

# ArtistQueen

def lookup(d, key):

found = False

for child in d:

if found : return child.text

if child.tag == 'key' and child.text == key :

found = True

return None

stuff = ET.parse(fname)

all = stuff.findall('dict/dict/dict')

print 'Dict count:', len(all)

for entry in all:

if ( lookup(entry, 'Track ID') is None ) : continue

name = lookup(entry, 'Name')

artist = lookup(entry, 'Artist')

album = lookup(entry, 'Album')

count = lookup(entry, 'Play Count')

rating = lookup(entry, 'Rating')

length = lookup(entry, 'Total Time')

genre = lookup(entry, 'Genre')

if name is None or artist is None or album or genre is None : continue

print name, artist, album, genre, count, rating, length

cur.execute('''INSERT OR IGNORE INTO Artist (name)

VALUES ( ? )''', ( artist, ) )

cur.execute('SELECT id FROM Artist WHERE name = ? ', (artist, ))

artist_id = cur.fetchone()[0]

cur.execute('''INSERT OR IGNORE INTO Album (title, artist_id)

VALUES ( ?, ? )''', ( album, artist_id ) )

cur.execute('SELECT id FROM Album WHERE title = ? ', (album, ))

album_id = cur.fetchone()[0]

cur.execute('''INSERT OR IGNORE INTO Genre (name)

VALUES ( ? )''', ( genre, ) )

cur.execute('SELECT id FROM Genre WHERE name = ? ', (genre, ))

genre_id = cur.fetchone()[0]

cur.execute('''INSERT OR REPLACE INTO Track

(title, album_id, genre_id, len, rating, count)

VALUES ( ?, ?, ?, ?, ?, ? )''',

( name, album_id, genre_id, length, rating, count ) )

conn.commit()

我缺少一个SELECT语句吗？我试图应用一个JOIN语句来显示所需的表，其中包括曲目、流派、专辑和艺术家的名字，但我真的不知道如何合并它。当我尝试genre_id=当前取款()[0]如果有人能给我一些见解，我将不胜感激。在

以下是指向XML数据的链接：

它基本上在不同的键/值对的字典中显示轨迹信息的字典。在

再次感谢。在