问题标题

设计三个类：几何形状类(Shape)、圆类(Circle)、矩形类(.,请编写 Java程序,设计一个“形状&rdquo

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问题补充：

设计三个类：几何形状类(Shape)、圆类(Circle)、矩形类(...,请编写 Java程序,设计一个“形状”基类,经由“形状”继承出3个子...

网友答案

用VB程序设计做的随机画十个圆的编程代码 抱歉：就知道这些Dim r(10) As Integer,i As Integer '半径Dim x(10) As Integer,n As Integer '半径坐标Dim y(10) As Integer,m As Integer '半径坐标Dim mr As IntegerPrivate Sub Command1_Click()Clsi = 1Text1 = ＂ ＂Text2 = ＂ ＂Timer1.Enabled = TrueCommand2.Enabled = TrueEnd SubPrivate Sub Command2_Click()Dim a As Integer,b As Integera = r(1)b = r(1)For i = 2 To 10If a r(i) Thenb = r(i)End IfNext iText1 = aText2 = bEnd SubPrivate Sub Command3_Click()EndEnd SubPrivate Sub Form_Load()i = 1n = 1m = 1End SubPrivate Sub Timer1_Timer()Randomizex(n) = Int(Rnd * (Frame1.Left - 99) + 100)y(m) = Int(Rnd * (Form1.ScaleHeight - 99) + 100)mr = x(n)If mr > y(m) Then mr = y(m)If mr > Frame1.Left - x(n) Then mr = Frame1.Left - x(n)If mr > Form1.ScaleHeight - y(m) Then mr = Form1.ScaleHeight - y(m)r(i) = Int((Rnd * mr - 51) + 100)Circle (x(n),y(m)),r(i),QBColor(Int(Rnd * 16)) 'RGB(Int(Rnd * 256),Int(Rnd * 256),Int(Rnd * 256))Form1.DrawWidth = Int(Rnd * 5 + 1)i = i + 1If i = 11 Then Timer1.Enabled = FalseEnd Sub

网友答案

用VB程序设计做的随机画十个圆的编程代码 抱歉： 就知道这些Dim r(10) As Integer, i As Integer '半径Dim x(10) As Integer, n As Integer '半径坐标Dim y(10) As Integer, m As Integer '半径坐标Dim mr As IntegerPrivate Sub Command1_Click()Clsi = 1Text1 = ＂ ＂Text2 = ＂ ＂Timer1.Enabled = TrueCommand2.Enabled = TrueEnd SubPrivate Sub Command2_Click()Dim a As Integer, b As Integera = r(1)b = r(1)For i = 2 To 10If a a = r(i)ElseIf b >r(i) Thenb = r(i)End IfNext iText1 = aText2 = bEnd SubPrivate Sub Command3_Click()EndEnd SubPrivate Sub Form_Load()i = 1n = 1m = 1End SubPrivate Sub Timer1_Timer()Randomizex(n) = Int(Rnd * (Frame1.Left - 99) + 100)y(m) = Int(Rnd * (Form1.ScaleHeight - 99) + 100)mr = x(n)If mr >y(m) Then mr = y(m)If mr >Frame1.Left - x(n) Then mr = Frame1.Left - x(n)If mr >Form1.ScaleHeight - y(m) Then mr = Form1.ScaleHeight - y(m)r(i) = Int((Rnd * mr - 51) + 100)Circle (x(n), y(m)), r(i), QBColor(Int(Rnd * 16)) 'RGB(Int(Rnd * 256), Int(Rnd * 256), Int(Rnd * 256))Form1.DrawWidth = Int(Rnd * 5 + 1)i = i + 1If i = 11 Then Timer1.Enabled = FalseEnd Sub

网友答案

你好，刚好闲着帮你写一个：Shape类：public class Shape {protected Point location;public Shape(){}public double area(){return 0.0;}}Circle类：public class Circle extends Shape{private int r;public Circle() {}public Circle(Point center,int r) {super.location=center;this.r = r;}public double area() {return Math.PI*r*r ;}}Rectangle类：public class Rectangle extends Shape{private int width;private int height;public Rectangle() {}public Rectangle(Point o,int width, int height) {location=o;this.width = width;this.height = height;}public double area() {return width*height;}}我这里图方便，在创建圆的时候直接用圆心和半径创建，还有矩形也是用一个点位置和长宽创建，所以还要加一个点类：public class Point {public int x;public int y;public Point() {}public Point(int x, int y) {this.x = x;this.y = y;}}

网友答案

// 完整代码如下： #include #include using namespace std; // PI定义 const double PI = 3.1415926; // Shape class Shape{ public: virtual double area(){ return 0; } virtual double girth(){ return 0; } virtual void show(){ coutShape Object:＂Circle class Circle : public Shape{ public: Circle():m_Radius(0) {} Circle(double radius):m_Radius(radius) {} ~Circle() {} double area(){ return m_Radius * m_Radius * PI; } double girth(){ return 2 * PI * m_Radius; } void show(){ coutCircle Object＂Shape{ public: Triangle():m_EdgeA(0), m_EdgeB(0), m_EdgeC(0) {} Triangle(double la, double lb, double lc):m_EdgeA(la), m_EdgeB(lb), m_EdgeC(lc) {} ~Triangle() {} double area(){ double temp = girth() * 0.5; return sqrt( temp * (temp-m_EdgeA) * (temp-m_EdgeB) * (temp-m_EdgeC) ); } double girth(){ return m_EdgeA + m_EdgeB + m_EdgeC; } void show(){ coutRectangle class Rectangle : public Shape{ public: Rectangle():m_Length(0), m_Width(0) {} Rectangle(double length, double width):m_Length(length), m_Width(width) {} ~Rectangle() {} double area(){ return m_Length * m_Width; } double girth(){ return 2 * (m_Length + m_Width); } void show(){ coutRectangle Object＂Shape *p1 = new Circle(2); Shape *p2 = new Triangle(3, 4, 5); Shape *p3 = new Rectangle(6, 7); // Area coutarea()area()area()girth()girth()girth()show(); p2->show(); p3->show(); delete p1; p1 = NULL; delete p2; p2 = NULL; delete p3; p3 = NULL; cout<

网友答案

public abstract class Shape {public abstract double area();}--------------------------------------------------public class Rectangle extends Shape {double length；//矩形的长double width；//矩形的宽public Rectangle(double len,double wid) {//构造方法this.length = len;this.width = wid;[email protected] double area) {//返回矩形的面积double area = length * width;return area;}}--------------------------------------------------public class Circle extends Shape {double radius；//圆的半径public Circle(double rad) {//构造方法this.radius = rad;[email protected] double area) {//返回园的面积double area = 3.14 * radius * radius;return area;}}--------------------------------------------------public class MyTest {//测试类public static void main(String args) {Rectangle rec = new Rectangle(4.7, 5.1);double recArea = rec.area();System.out.println＂矩形的长5.1，宽4.7，面积：＂ + recArea;Circle cir = new Circle(6.4);double cirArea = cir.area();System.out.println＂园的半径6.4，面积：＂ + cirArea;}}

网友答案

#includeusing namespace std;class Shape{public:virtual double peri()=0;};class Rect : public Shape{double length;double width;public:Rect(double len=2,double w=1){length=len; width=w;}double peri(){ return 2*(length+width); }};void main(){Rect r(1, 1);Shape *p=&r;coutperi();}

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