javafor循环打印图案

Input a number and print the following box pattern in C language,

输入数字并以C语言打印以下框形 ，

    4 4 4 4 4 4 4
4 3 3 3 3 3 4
4 3 2 2 2 3 4
4 3 2 1 2 3 4
4 3 2 2 2 3 4
4 3 3 3 3 3 4
4 4 4 4 4 4 4

Input format:

输入格式：

The input will contain a single integer.

输入将包含一个整数。

Constraints:

限制条件：

1<=n<=100

1 <= n <= 100

Output format:

输出格式：

Print the pattern mentioned in the problem statement.

打印问题陈述中提到的模式。

Example

例

    Input:
2
Output:
2 2 2
2 1 2
2 2 2

代码以C语言打印盒子图案 (Code to print the box pattern in C)

//Code to print the box pattern in C
#include <stdio.h>
int main()
{int n, i, j, t; //n is representing number of the output box
//input n
printf("Enter the value of n: ");
scanf("%d", &n);
t = 2 * n - 1;
i = t; //i and j are the number of rows and columns of the box.
j = t;
// Declare box as a 2-D matrix having i number of rows
//and j number of columns
int a[i][j], k, m, p;
p = n;
m = 0;
for (k = 0; k < p; k++) {for (i = m; i < t; i++) {for (j = m; j < t; j++) {if (i == m || i == (t - 1) || j == m || j == (t - 1)) {a[i][j] = n;
if (n == 1) {break;
}
}
}
}
t = t - 1;
n = n - 1;
m = m + 1;
}
t = 2 * m - 1;
for (i = 0; i < t; i++) {for (j = 0; j < t; j++) {printf("%d ", a[i][j]);
}
printf("\n");
}
return 0;
}

Output

输出量

First run:
Enter the value of n: 2
2 2 2
2 1 2
2 2 2
Second run:
Enter the value of n: 4
4 4 4 4 4 4 4
4 3 3 3 3 3 4
4 3 2 2 2 3 4
4 3 2 1 2 3 4
4 3 2 2 2 3 4
4 3 3 3 3 3 4
4 4 4 4 4 4 4

翻译自: https://www.includehelp.com/c-programs/print-box-pattern-using-loops.aspx

javafor循环打印图案