Subarray Sum

Given an integer array, find a subarray where the sum of numbers is zero. Your code should return the index of the first number and the index of the last number.

Given [-3, 1, 2, -3, 4], return [0, 2] or [1, 3].

考察集合

思路：累加数组的每一个元素，当和出现重复时表明该范围内存在子数组子和为0的情况。

　　　1.建立HashMap key:为数组的值，value：为数组的下标。

　　　2.遍历数组求和。查找和是否在HashMap中出现，出现则表明存在子数组和为0。否则，将sum和下标加入map中。

public class Solution {public ArrayList<Integer> subArraySum (int[] nums) {ArrayList<Integer> ans = new ArrayList<>();if (nums == null || nums.length == 0) {return 0;}HashMap<Integer, Integer> map = new HashMap<>();map.put(0, -1);int sum = 0;for (int i = 0; i < nums.length; i++) {sum += nums[i];if (map.containsKey(sum)) {ans.add(map.get(sum) + 1);ans.add(i);} else {map.put(sum, i);}}return ans;}
}

转载于:https://www.cnblogs.com/FLAGyuri/p/5260516.html

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