有一个需求用谷歌地图绘制一个图形，获取图形范围内有哪些标记点。我试着看谷歌地图的js文档，发现里面有此类的功能。

文档链接：谷歌地图api

我来分享一下使用方法：

//核心方法
google.maps.geometry.poly.containsLocation('经纬度对象', '图形实例')

let graphicalPath = [];
let graphicalExample = null;//绘制图形的实例
let package_list = [];//标记点数据
function setDrawingModes() {//开始实例化绘制工具库let drawingModesList = {MARKER: google.maps.drawing.OverlayType.MARKER,CIRCLE: google.maps.drawing.OverlayType.CIRCLE,POLYGON: google.maps.drawing.OverlayType.POLYGON,POLYLINE: google.maps.drawing.OverlayType.POLYLINE,RECTANGLE: google.maps.drawing.OverlayType.RECTANGLE,};const drawingManager = new google.maps.drawing.DrawingManager({drawingControl: true,drawingControlOptions: {position: google.maps.ControlPosition.TOP_CENTER,drawingModes: [drawingModesList.POLYGON],},polygonOptions: {fillColor: "blue",strokeColor: "blue",strokeOpacity: 0.8,fillOpacity: 0.4,strokeWeight: 5,clickable: false,editable: true,zIndex: 1,},polylineOptions: {fillColor: "blue",strokeColor: "blue",strokeOpacity: 0.8,fillOpacity: 0.4,strokeWeight: 5,clickable: false,editable: true,zIndex: 1,},});drawingManager.setMap(map);//监听绘制多边形完成事件事件google.maps.event.addListener(drawingManager, "polygoncomplete", (e) => {let path = e.getPath().getArray();//存在就清除上一个图形if (graphicalExample) {graphicalExample.setMap(null);}graphicalExample = e;setPath(path);//监听回显图形每一个路径点google.maps.event.addListener(e.getPath(), "insert_at", (event) => {setPath(path);});google.maps.event.addListener(e.getPath(), "set_at", (event) => {setPath(path);});//绘制完成后关闭绘制状态drawingManager.setDrawingMode(null);});
}function setPath(path) {let graphicalPath = []path.forEach((v) => {graphicalPath.push({ lat: v.lat(), lng: v.lng() })})package_list.forEach(v=>{//graphicalExample图形实例if(google.maps.geometry.poly.containsLocation({ lat: v.lat*1, lng: v.long*1 }, graphicalExample) == true){//等于true就在图形范围内console.log(v);}})
}